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hoa [83]
3 years ago
10

Could someone help me on this math question please!! I don't remember what to do for things like these!

Mathematics
2 answers:
Bas_tet [7]3 years ago
7 0
The answer to your question is C. 4

velikii [3]3 years ago
5 0
B) is the answer to the question.
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Answer:

The 95% confidence interval for the true average strain is between 23.94% and 28.06%.

Step-by-step explanation:

We have the standard deviation of the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 13 - 1 = 12

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 12 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.18

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.18\frac{3.4}{\sqrt{13}} = 2.06

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 26 - 2.06 = 23.94

The upper end of the interval is the sample mean added to M. So it is 26 + 2.06 = 28.06

The 95% confidence interval for the true average strain is between 23.94% and 28.06%.

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If the interest of a sum at 7.5% p.a in 4 years is rs 1050, find the sum​
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