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3 years ago

A scale on a hiking map shows that 3 inches represents 1.25, miles.

Mathematics

1 answer:

daser333 [38]3 years ago

4 0

Answer:

415

Step-by-step explanation:

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When rolling a number cube numbered 1 to 6, how would you describe the chances of rolling a number greater than or equal to 3 ve

katrin2010 [14]

The answer is A because there is a higher chance of the number cube rolling a 3,4,5 or 6 than the cube rolling a 1 or 2. It’s 4 against 2

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3 years ago

Haley solving this problem by combining like terms 3x +5x=10

GaryK [48]

Answer:

x = 5/4

Step-by-step explanation:

By combining like terms, you get 8x = 10.

Divide the 8 on both sides of the equation.

x = 10/8

This, however, can be simplified by dividing by 2. This ultimately gives us 5/4.

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3 years ago

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irinina [24]

Since that is a triangle the expression would be b x h / 2. So 12*12 = 144 / 2 = 72. The answer is 72.

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3 years ago

in a candy store a $5 jar of candy is labeled 50% off what is the discount what is the sale price of the jar of candy

beks73 [17]

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3 years ago

Let A and B be events with =PA0.7, =PB0.3, and =PA or B0.9. (a) Compute PA and B. (b) Are A and B mutually exclusive? Explain. (

kvasek [131]

Answer:

a) $P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

b) False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

c) False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

Step-by-step explanation:

For this case we have the following probabilities given:

$P(A) = 0.7, P(B) =0.7, P(A \cup B) =0.9$

Part a

We want to calculate the following probability: $P(A \cap B)$

And we can use the total probability rule given by:

$P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

Part b

False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

Part c

False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

4 0

3 years ago