7 < 2m - 23
add 23 to both sides
30 < 2m
divide both sides by 2
15 < m
same as m > 15
Answer:
2.
A. (P+h)(x)
2x/x+4 (x-1) + x/x-1 (x+4)
2x^2-1/x^2-4
+
X^2+4/x^2-4
= 3x^2+3/x^2-4
B. (F-g)(x)
X^2-7x+6-x - 6
= x^2 -8x
C. (Fg)(x)
(X^2-7x+6)(x-6)
= x^3-13x^2+48x-36
D. (H/p)(x)
X/x-1 / 2x/x+4
X/x-1 / x+4/2x
= X^2+4x/2x^2-2x
3.
A. (F+g)(3)
X^2+1 + x-4
3^2+1 + 3-4
10 -1
= 9
B. (f-g)(0)
X^2+1 - x-4
0+1 -0-4
1-4
= -3
C. (Fg)(-k)
(X^2+1) (x-4)
(-k^2+1) (-k-4)
K^3+4k^2-k-4
D. (F/g)(k-2)
X^2+1 /x-4
K-2^2+1 / k-2 -2
= K^2-4k+5 / k-4
Step-by-step explanation:
Answer:
18.045
Step-by-step explanation:
because you will have 18liters and because of 045 you would let it stay the same and instead of a coma you would put a period.
hop this helps
The first case occurs in
for
and
. Extending the domain to account for all real
, we have this happening for
and
, where
.
The second case occurs in
when
, and extending to all reals we have
for
, i.e. any even multiple of
.
Answer:
Reflection!!!
Step-by-step explanation:
Hope this helps!
