Ask question

Ask question

All categories

Juli2301 [7.4K]

2 years ago

14

PLEASE HELP !!!! i literally dont know what im doing and i need to start getting ready for work but im really trynna finish this

so please someone help. NO LINKS OR FILES OR I WILL REPORT

1 answer:

Gala2k [10]2 years ago

5 0

Answer:

(x + 6) (x + 8)

explanation:

x times x = x^2

6 x 8 = 48

6 +8 = 14

You might be interested in

Amy is training for a half marathon. in practice, she runs 2 miles in 15 minutes. If she continues at the same rate, how many mi

kipiarov [429]

Step-by-step explanation:

B. 8

she will run for 8 miles,

<h2>step</h2>

find Amy's speed

convert the minutes into hours by dividing by 60

$\frac{2}{15 \times \frac{1}{60} } \\ = 8 \: miles \: per \: hour$

find the number of miles ran by multiplying the speed by the time, ie

$8 \times 1 = 8 \\ \: therefore \: the \: answer \: is \: \: 8 \: miles$

3 0

2 years ago

How do you answer this question? It's my sisters, me and my mom have never seen it before. Number 7

algol [13]

I think that the answer is A because you are being asked for the tens place. Since you are looking to identify the place value, choice B and C are automatically eliminated because each place value increases by multiplying by ten. 20 and 60 are not multiples of 10. To identify the tens place, you would have to multiply by ten. I thought of this question in the sense of scientific notations.

6 0

2 years ago

Read 2 more answers

a music store is advertising a 25% off sale on all new releases find the discount and the sale price of a newly released CD that

ludmilkaskok [199]

Discount=$3.13
sale=$9.38

4 0

2 years ago

Let φ(x, y) = arctan (y/x) .

Alexandra [31]

Answer:

a) $\large F(x,y)=(-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})$

b) $\large \mathbb{R}^2-\{(0,0)\}$

c) the points of the form (x, -x) for x≠0

Step-by-step explanation:

a)

If φ(x, y) = arctan (y/x), the vector field F = ∇φ would be

$\large F(x,y)=(\frac{\partial \phi}{\partial x},\frac{\partial \phi}{\partial y})$

On one hand we have,

$\large \frac{\partial \phi}{\partial x}=\frac{\partial arctan(y/x)}{\partial x}=\frac{-y/x^2}{1+(y/x)^2}=-\frac{y/x^2}{1+y^2/x^2}=\\\\=-\frac{y/x^2}{(x^2+y^2)/x^2}=-\frac{y}{x^2+y^2}$

On the other hand,

$\large \frac{\partial \phi}{\partial y}=\frac{\partial arctan(y/x)}{\partial y}=\frac{1/x}{1+(y/x)^2}=\frac{1/x}{1+y^2/x^2}=\\\\=\frac{1/x}{(x^2+y^2)/x^2}=\frac{x}{x^2+y^2}$

So

$\large F(x,y)=(-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})$

b)

The domain of definition of F is

$\large \mathbb{R}^2-\{(0,0)\}$

i.e., all the plane X-Y except the (0,0)

c)

Here we want to find all the points such that

$\large (-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})=(k,k)$

where k is a real number other than 0.

But this means

$\large -\frac{y}{x^2+y^2}=\frac{x}{x^2+y^2}\Rightarrow y=-x$

So, all the points in the line y = -x except (0,0) are parallel to the vector field F, that is, the points (x, -x) with x≠ 0

8 0

2 years ago

H/6-1=-3. What is h?

Marrrta [24]

$\dfrac{h}{6}-1=-3\\\\
\dfrac{h}{6}=-2\\\\
h=-12$

8 0

2 years ago