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notka56 [123]
2 years ago
11

\text{Emily runs 11 feet per second.}

Mathematics
1 answer:
Stels [109]2 years ago
3 0

Answer:

Not sure what the question is but if you're looking for who runs the most in a second I can give you that

Emily: 11 feet per second

Will: 9.66 feet per second

Stephanie: 13.27 feet per second

Liz: 8.98 feet per second

Based off this info, Stephanie runs the fastest per second

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Konrad raised $75.50 for his football team. He raised 151% of his fundraising goal how much more then his fundraising did Konrad
Colt1911 [192]

Answer:

He raised $25.50 over his fund raising goal

Step-by-step explanation:

Here, we want to calculate his fund raising goal.

Let his fund raising goal be $x

We are told that he raised 151% of his fundraising goal;

Thus,

mathematically;

151% of x = 75.5

151/100 * x = 75.5

151x = 100 * 75.5

151x = 7550

x = 7550/151

x = $50

So the amount he raised over his fund raising goal will be $75.50 - $50 = $25.50

8 0
3 years ago
The function g is defined as follows for the domain given. g(x) = 2 - 2x , domain = \{- 1, 0, 1, 2\} Write the range of g using
Musya8 [376]

Explanation:

The function is given below as

g(x)=2-2x

The set of domains is given below as

\lbrace-1,0,1,2\rbrace

Step 1:

Put x=-1

\begin{gathered} g(x)=2-2x \\ g(-1)=2-2(-1) \\ g(-1)=2+2 \\ g(-1)=4 \end{gathered}

Step 2:

Put x=0

\begin{gathered} g(x)=2-2x \\ g(0)=2-2(0) \\ g(0)=2 \end{gathered}

Step 3:

Put x=1

\begin{gathered} g(x)=2-2x \\ g(1)=2-2(1) \\ g(1)=2-2 \\ g(1)=0 \end{gathered}

Step 4:

Put x=2

\begin{gathered} g(x)=2-2x \\ g(2)=2-2(2) \\ g(2)=2-4 \\ g(2)=-2 \end{gathered}

Hence,

The range of g(x) using set notation will be

\Rightarrow\lbrace4,2,0,-2\rbrace

Hence,

The graph of g(x) is given below as

8 0
1 year ago
Helphelphelphelphelphelppppppp
n200080 [17]

Answer:

Step-by-step explaSimplify the equation by finding the square root of both sides. √x2=x √0=0. x=0. Check: 02=0.

5 0
3 years ago
Help me...
katen-ka-za [31]
<h2>>> Answer </h2>

________

3y + 1 = 10

3y = 10 - 1

3y = 9

y = 9 ÷ 3

y = 3

6 0
3 years ago
Read 2 more answers
Write an equation of the hyperbola given that the center is at (2, -3), the vertices are at (2, 3) and (2, - 9), and the foci ar
zavuch27 [327]
Check the picture below.

so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).

because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

\bf \textit{hyperbolas, vertical traverse axis }&#10;\\\\&#10;\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1&#10;\qquad &#10;\begin{cases}&#10;center\ ( h, k)\\&#10;vertices\ ( h,  k\pm a)\\&#10;c=\textit{distance from}\\&#10;\qquad \textit{center to foci}\\&#10;\qquad \sqrt{ a ^2 + b ^2}\\&#10;asymptotes\quad  y= k\pm \cfrac{a}{b}(x- h)&#10;\end{cases}\\\\&#10;-------------------------------

\bf \begin{cases}&#10;h=2\\&#10;k=-3\\&#10;a=6\\&#10;c=2\sqrt{10}&#10;\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1&#10;\\\\\\&#10;\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1&#10;\\\\\\&#10;c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2&#10;\\\\\\&#10;4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2&#10;\\\\\\&#10;\sqrt{4}=b\implies 2=b\\\\&#10;-------------------------------\\\\&#10;\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

3 0
3 years ago
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