32/100 simplest form

Find the miing value in the ratio table. Then write the equivalent ratio. Plum 14 42 Grape 7 3 24 The equivalent ratio are 14 :

denis-greek [22]

The equivalent ratio is 8 : 4.

And the missing values are as follows 21, 6 and 48.

Complete table be,

Plum 14 42 6 48

Grape 7 21 3 24

Given, a ratio table

Plum 14 42 __ __

Grape 7 __ 3 24

we have to find the missing values and the equivalent ratios.

in the first ratio,

Plum : Grape = 14 : 7 = 2 : 1

Now, in the second ratio,

2 : 1 = 42 : __

x = 21

Now, in the third ratio,

2 : 1 = __ : 3

x = 6

Now, in the forth ratio,

2 : 1 = __ : 24

x = 48

So, the equivalent ratio is 8 : 4.

And the missing values are as follows 21, 6 and 48.

Hence, the equivalent ratio is 8 : 4.

And the missing values are as follows 21, 6 and 48.

Complete table be,

Plum 14 42 6 48

Grape 7 21 3 24

Learn more about Ratios and Proportions here brainly.com/question/26974513

#SPJ4

4 0

1 year ago

The scale on a map is 2cm= 1km. Express this as a ratio

Lemur [1.5K]

This would mean that the ratio is 2:1 or 2 to 1 or also 2/1.

The ratio would be that because it's 2 centimeters per 1 kilometer.

7 0

3 years ago

Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5

givi [52]

<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

$A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]$ $X=\left[\begin{array}{c}x\\y\end{array}\right]$

and $B= \left[\begin{array}{c}11\\5\end{array}\right]$

∴AX=B

$adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]$

$A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6$

∴ $A^{-1} =\frac{adj A}{|A|}$

So, $A^{-1} =\frac{ \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]}{-6}$

$A^{-1} ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}$

$X =A^{-1}\times B$

⇒ $\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]$

⇒ $\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c} {6}\\ {11} \end{array}\right]}$

∴ x= 6 and y = 11

The required solution is x = 6 and y = 11

7 0

3 years ago

Un cono ha l'area laterale di 255 pigreco cm^2, l'apotema di 17 cm e pesa 900 pigreco g. Calcola il peso specifico del materiale

valkas [14]

Answer:

The specific weight is $1.5\frac{g}{cm^{3}}$

Step-by-step explanation:

The question in English

A cone has a lateral area of 255 pi cm^2, an apothem of 17 cm and weighs 900 pi g. It calculates the specific weight of the material of which it is composed

step 1

Find the radius of the cone

we know that

The lateral area of a cone is equal to

$LA=\pi rl$