All categories

3 years ago

Compare the values of the underlined digits .. 2,783 and 7,283

Mathematics

1 answer:

alisha [4.7K]3 years ago

3 0

Answer:

the second is bigger the whole part is 7 which is bigger than 2. if the whole parts are different you don't need to compare decimal parts

You might be interested in

8. The high school graduating class of 2000 was 260 students. Five years later, the graduating class was 320 students. By 2010,

olga nikolaevna [1]

Answer:

the question is confusing but the answer is 2010

Step-by-step explanation:

because in the year 2000 it was

260

then increased by

over 5 years making the next class

320

then in 2010 it was

400

and 320 + what is 400?

so the answer is:

2010

4 0

2 years ago

Subtract and simplify <br> 1/6m - (- 5/8m + 1/3)

ratelena [41]

Answer:

19/24m-1/3

Step-by-step explanation:

1/6m-(-5/8m+1/3)=1/6m+5/8m-1/3=4/24m+15/24m-1/3=19/24m-1/3

4 0

2 years ago

The manufacturer of Pepsi claims that its 2-liter bottles contain, on average, no more than 250 calories. A sample of 20 2-liter

Stels [109]

Answer:

Yes, Sample information does indicate that a 2-liter bottle of Pepsi contains more than 250 calories

Step-by-step explanation:

Null Hypothesis [H0] : u < 250

Alternate Hypothesis [H1] : u > 250 {One Tail}

t = (x' - u) / [ sd / √n ]

= (255 - 250) / (5.6 / √20)

5 / (5.6 /√20)

= 3.99

As t ie 3.99 > t value 1.65 ie for one tail 95% confidence level. So, we reject the null hypothesis & conclude that it contains more than 250 calories.

4 0

2 years ago

What is 8)55 with the remainder.

Lady bird [3.3K]

That would be 6.875 .

6 0

2 years ago

Read 2 more answers

Let A and B be events with =PA0.7, =PB0.3, and =PA or B0.9. (a) Compute PA and B. (b) Are A and B mutually exclusive? Explain. (

kvasek [131]

Answer:

a) $P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

b) False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

c) False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

Step-by-step explanation:

For this case we have the following probabilities given:

$P(A) = 0.7, P(B) =0.7, P(A \cup B) =0.9$

Part a

We want to calculate the following probability: $P(A \cap B)$

And we can use the total probability rule given by:

$P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

Part b

False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

Part c

False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

4 0

3 years ago