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Bad White [126]
2 years ago
12

Yasmin purchased 6 heads of cabbage that each weighed 2 3/8 pounds. How much did the cabbage weigh all together?

Mathematics
1 answer:
nika2105 [10]2 years ago
3 0

Answer:

14\frac{1}{4} pounds

Step-by-step explanation:

Here we have to use multiplication.

Yamin purchased 6 heads of cabbage.

The weight of each cabbage = 2 \frac{3}{8}

First let's convert the mixed fraction 2\frac{3}{8} to improper fraction

2\frac{3}{8} = \frac{19}{8}

The weight of 6 heads of cabbage = 6 x \frac{19}{8}

= 114/8

= 14 \frac{2}{8}

We can reduce 2/8 = 1/4

= 14 \frac{1}{4}

Thank you.

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Step-by-step explanation:

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8 0
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Arte-miy333 [17]

Answer:

Answer is option d)346.4 ft

Step-by-step explanation:

from \: the \: figure \\ AB = 300 \: ft \:  \:  \: angle \: C = 60  \:( theta)\: degress \\ in \: triangle \: ABC \: using \:  tan \: theta\\  \tan(60)  =  \frac{opposite \: side}{adjacent \: side}  \\  \tan(60)  =  \frac{300}{BC}  \\  \sqrt{3}  =  \frac{300}{BC}  \\ BC =  \frac{300}{ \sqrt{3} }  \\ BC = 100 \sqrt{3} ft \\ then \: in \: triangle \: ABD \: using \: tan \: theta \\ angle \: D = 30 \: degrees \: (theta) \\   \tan(30 )  =\frac{opposite \: side}{adjacent \: side} \\  \tan(30)   =  \frac{300}{BD}  \\  \frac{1}{ \sqrt{ 3} }  =  \frac{300}{BD}  \\ BD = 300 \sqrt{3}  \\ CD = BD - BC \\  = 300 \sqrt{3 }  - 100 \sqrt{3}  \\  = (300 - 100) \sqrt{3}  \\  = 200 \sqrt{3 }  \\  = 200 \times 1.732 \\  = 346.4 \: ft

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

7 0
3 years ago
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Step-by-step explanation:

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5 0
2 years ago
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