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3 years ago

14

An engineer is standing 250 meters away from a building. She measures the angle of elevation to the top of the building to be 30

degrees. How tall is the building, rounded to the nearest meter?

1 answer:

RSB [31]3 years ago

3 0

Answer:

144m

Step-by-step explanation:

we would used tan 30 to determine the height of the building

tan 30 = opposite / adjacent

0.5774 x 250 = 144m

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Given the quadratic equation <img src="https://tex.z-dn.net/?f=y%20%3D%202%28x%20-1%29%5E%7B2%7D%20%2B%208" id="TexFormula1" tit

Sunny_sXe [5.5K]

Answer:

Part 1) "a" value is $2$

Part 2) The vertex is the point $(1,8)$

Part 3) The equation of the axis of symmetry is $x=1$

Part 4) The vertex is a minimum

Part 5) The quadratic equation in standard form is $y=2x^{2}-4x+10$

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

$y=a(x-h)^{2}+k$

where

(h,k) is the vertex of the parabola

if a > 0 then the parabola open upward (vertex is a minimum)

if a < 0 then the parabola open downward (vertex is a maximum)

The equation of the axis of symmetry of a vertical parabola is equal to the x-coordinate of the vertex

so

$x=h$

In this problem we have

$y=2(x-1)^{2}+8$ -----> this is the equation in vertex form of a vertical parabola

The value of $a=2$

so

a>0 then the parabola open upward (vertex is a minimum)

The vertex is the point $(1,8)$

so

$(h,k)=(1,8)$

The equation of the axis of symmetry is $x=1$

The equation of a vertical parabola in standard form is equal to

$y=ax^{2}+bx+c$

Convert vertex form in standard form

$y=2(x-1)^{2}+8$

$y=2(x^{2}-2x+1)+8$

$y=2x^{2}-4x+2+8$

$y=2x^{2}-4x+10$

see the attached figure to better understand the problem

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3 years ago

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luda_lava [24]

93/4

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13/4=4r1

10/4=2r2

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=23.25

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ICE Princess25 [194]

Answer:

Step-by-step explanation:

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The product of a number and 4 is three times the sum of that number and 6

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Answer:

24?

Step-by-step explanation:

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BlackZzzverrR [31]

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