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Luda [366]
3 years ago
5

Hence solve the equation x^3+x^2-6x=0​

Mathematics
2 answers:
Sever21 [200]3 years ago
8 0

Answer:x³ + x² - 6x = 0

x(x² + x - 6) = 0

x(x² + 3x - 2x - 6) = 0

x[x(x + 3) - 2(x + 3)] = 0

x(x - 2)(x + 3) = 0

x₁ = 0

x - 2 = 0 => x₂ = 2

x + 3 = 0 => x₃ = - 3

Step-by-step explanation:

Aneli [31]3 years ago
4 0

<em>Answer:</em>

<em />

<em>x³ + x² - 6x = 0</em>

<em>x(x² + x - 6) = 0</em>

<em>x(x² + 3x - 2x - 6) = 0</em>

<em>x[x(x + 3) - 2(x + 3)] = 0</em>

<em>x(x - 2)(x + 3) = 0</em>

<em>x₁ = 0</em>

<em>x - 2 = 0 => x₂ = 2</em>

<em>x + 3 = 0 => x₃ = - 3</em>

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Step-by-step explanation:

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