Hence solve the equation x^3+x^2-6x=0
2 answers:
Answer:x³ + x² - 6x = 0
x(x² + x - 6) = 0
x(x² + 3x - 2x - 6) = 0
x[x(x + 3) - 2(x + 3)] = 0
x(x - 2)(x + 3) = 0
x₁ = 0
x - 2 = 0 => x₂ = 2
x + 3 = 0 => x₃ = - 3
Step-by-step explanation:
<em>Answer:</em>
<em />
<em>x³ + x² - 6x = 0</em>
<em>x(x² + x - 6) = 0</em>
<em>x(x² + 3x - 2x - 6) = 0</em>
<em>x[x(x + 3) - 2(x + 3)] = 0</em>
<em>x(x - 2)(x + 3) = 0</em>
<em>x₁ = 0</em>
<em>x - 2 = 0 => x₂ = 2</em>
<em>x + 3 = 0 => x₃ = - 3</em>
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