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2 years ago

Write an equation of the line in slope-intercept form given the slope is 2 and the y-intercept is -5.

Mathematics

1 answer:

AveGali [126]2 years ago

7 0

Answer:

y=2x-5

Step-by-step explanation:

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Select the correct answer.

Brums [2.3K]

ответ: д
-1/2 * 16 = -8
или 16/(-2) = -8

4 0

1 year ago

Function f is graphed. According to the graph, is f even, odd, or neither?

miss Akunina [59]

Answer:

Step-by-step explanation:

f is neither even nor odd

3 0

3 years ago

What square root is closest to 5

nikklg [1K]

Answer: 2.236

Step-by-step explanation: The square root of 5 is expressed as √5 in the radical form and as (5)½ or (5)0.5 in the exponent form. The square root of 5 rounded up to 5 decimal places is 2.23607. It is the positive solution of the equation x2 = 5.

7 0

2 years ago

A parallelogram has an area of 60 square inches. If the base of the parallelogram is 12 inches, what is the height of the parall

Vikentia [17]

How to find the area of a parallelogram is length times height. 12 times what gets you to 60? 5 does. 12 times 5 is 60.

HEIGHT: 5

8 0

2 years ago

Complete the square to factor X^2 +10X=-8

ella [17]

Answer: $x=\sqrt{17}-5$ and $x = -\sqrt{17}-5$

Step-by-step explanation:

Alright, lets get started.

The given equation is :

$x^{2} +10x = -8$

Adding 8 in both sides, it will become

$x^{2} +10x + 8 = -8 +8$

$x^{2} +10x + 8 = 0$

To make it perfect square, we need to add 25 and subtract 25

$x^{2} +10x + 8 +25-25= 0$

$x^2+10x+25+8-25=0$

$(x+5)^2+8-25=0$

$(x+5)^2-17=0$

Adding 17 in both sides

$(x+5)^2=17$

taking square root

$x+5=\sqrt{17}$

So,

$x=\sqrt{17}-5$ and $x = -\sqrt{17}-5$ .. Answer

Hope it will help :)

7 0

2 years ago

Read 2 more answers