All you need to do is divide .88 by 6.8.
.88/6.8= 0.129 (round upt to .13 cents)
I hope this helps!
Answer:

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795
Step-by-step explanation:
Given
See attachment for class
Solving (a): Fill the midpoint of each class.
Midpoint (M) is calculated as:

Where
Lower class interval
Upper class interval
So, we have:
Class 63-65:

Class 66 - 68:

When the computation is completed, the frequency distribution will be:

Solving (b): Mean and standard deviation using 1-VarStats
Using 1-VarStats, the solution is:


<em>See attachment for result of 1-VarStats</em>
Answer:
0.0274
Step-by-step explanation:
The mean is
and the standard deviation is 
Calculate
for 
If
then 
and

Use table for normal distribution probabilities to get that

Answer:
it is 5 feet squared
Step-by-step explanation:
multiply them all
It is the average distance between each data value and the mean<span>.</span>