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Elodia [21]
3 years ago
13

The product of 9, and a number increased by 7, is 126. What is the number

Mathematics
1 answer:
RoseWind [281]3 years ago
6 0

Answer:

The number is 7.

Step-by-step explanation:

The unknown number: x

9 (x + 7) = 126

Using the distributive property, 9x + 63 = 126

9x = 63

x = 7

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The polynomial of degree 5, P ( x ) has leading coefficient a=1, has roots of multiplicity 2 at x = 3 and x = 0 , and a root of
ser-zykov [4K]

Answer:

p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}, for r_{1} = 0

Step-by-step explanation:

The general form of quintic-order polynomial is:

p_{5}(t) = a\cdot x^{5} + b\cdot x^{4} + c\cdot x^{3} + d\cdot x^{2} + e \cdot x + f

According to the statement of the problem, the polynomial has the following roots:

p_{5} (t) = (x - r_{1})\cdot (x-3)^{2}\cdot x^{2} \cdot (x+1)

Then, some algebraic handling is done to expand the polynomial:

p_{5} (t) = (x - r_{1}) \cdot (x^{3}-6\cdot x^{2}+9\cdot x) \cdot (x+1)\\p_{5} (t) = (x - r_{1}) \cdot (x^{4}-5\cdot x^{3} + 3 \cdot x^{2} + 9 \cdot x)

p_{5} (t) = x^{5} - (5+r_{1})\cdot x^{4} + (3 + 5\cdot r_{1})\cdot x^{3} +(9-3\cdot r_{1})\cdot x^{2} - 9 \cdot r_{1}\cdot x

If r_{1} = 0, then:

p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}

5 0
3 years ago
If x is 5, then 6x= __.
Misha Larkins [42]

Answer:

30

Step-by-step explanation:

Plug in x:

6(5)=30

5 0
3 years ago
Read 2 more answers
How many times bigger is 10 to the 11th power than 10 to the 3rd power?
Lapatulllka [165]

10^11 is 100,000,000,000

10^3 is 1000

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I think it might be 4 times bigger

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3 years ago
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Natasha2012 [34]

Answer:

No, does not differ.

Step-by-step explanation:

Given that there are two intersections route 7 and route 62.

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Let p1 be the first proportion and p2 the second

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(two tailed test at 5% significance level)

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p_1 = 0.1363\\p_2 = 0.1093

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p value = 0.4473

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Simplify the expression. -5a 3b 8a
slega [8]
Here is u answer -5a4b<span>8</span>
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3 years ago
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