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3 years ago

The product of 9, and a number increased by 7, is 126. What is the number

Mathematics

1 answer:

RoseWind [281]3 years ago

6 0

Answer:

The number is 7.

Step-by-step explanation:

The unknown number: x

9 (x + 7) = 126

Using the distributive property, 9x + 63 = 126

9x = 63

x = 7

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Y= x/8 rate is 1 to 1/8

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2 years ago

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65÷5=____ with ____ left over

Molodets [167]

65 ÷ 5 = 11 with 0 left over

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2 years ago

Which of the following is an equivalent expression to the expression a1/3 / a1/4

mixas84 [53]

Answer:

Option A :- $\sf {a}^{\frac{1}{12}}$

Step-by-step explanation:

$\hookrightarrow \sf \: \frac{ {a}^{ \frac{1}{3} } }{ {a}^{ \frac{1}{4} } }$

Simplify the expression

$\hookrightarrow \sf \: {a}^{ \frac{1}{3} - \frac{1}{4} }$

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2 years ago

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Pachacha [2.7K]

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3 years ago

Scientists modeled the intensity of the sun, I, as a function of the number of hours since 6:00 a.m., h, using the

MAVERICK [17]

The functions are illustrations of composite functions.

<em>The soil temperature at 2:00pm is 67</em>

The given parameters are:

$\mathbf{I(h) =\frac{12h - h^2}{36}}$ ---- the function for sun intensity

$\mathbf{T(I) =\sqrt{5000I}}$ -- the function for temperature

At 2:00pm, the value of h (number of hours) is:

$\mathbf{h = 2:00pm - 6:00am}$

$\mathbf{h = 8}$

Substitute 8 for h in $\mathbf{I(h) =\frac{12h - h^2}{36}}$ , to calculate the sun intensity

$\mathbf{I(8) =\frac{12 \times 8 - 8^2}{36}}$

$\mathbf{I(8) =\frac{32}{36}}$

$\mathbf{I(8) =\frac{8}{9}}$

Substitute 8/9 for I in $\mathbf{T(I) =\sqrt{5000I}}$ , to calculate the temperature of the soil

$\mathbf{T(8/9) =\sqrt{5000 \times 8/9}}$

$\mathbf{T(8/9) =\sqrt{4444.44}}$

$\mathbf{T(8/9) =66.67}$

Approximate

$\mathbf{T(8/9) =67}$

Hence, the soil temperature at 2:00pm is 67

Read more about composite functions at:

brainly.com/question/20379727

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2 years ago