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2 years ago

Please help! What is the product in the form ax^2+bx+c

Mathematics

1 answer:

Firlakuza [10]2 years ago

3 0

Answer:

a=2, b=2, c=-12

Step-by-step explanation:

Since it's in factor form, you would first distribute using foil to get $2x^{2} -4x+6x-12$ and then combine like terms when necessary. In this case, the fully simplified version is $2x^{2} +2x-12$ . Therefore your a is 2, b is 2, and c is -12.

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2 years ago

A particle moves with velocity vector

asambeis [7]

Answer:

$\vec{s(t)}=\frac{1}{2}t^2\hat{i}-(2t+1)\hat{j}+(\frac{1}{3}t^3+1)\hat{k}$

Step-by-step explanation:

We are given that velocity vector of a particle

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Integrate on both sides then we get

$\vec{s(t)}=\frac{1}{2}t^2\hat{i}-2t\hat{j}+\frac{1}{3}t^3\hat{k}+C$

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Substitute the value of point at time t=0 then we get

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2 years ago

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Answer:

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Step-by-step explanation:

I took the whole numbers and multiplied them by 3 and added them to the numerators, so I did 5/3 - 7/3, which would be -2/3

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Please help! What is the product in the form ax^2+bx+c​

Please help! What is the product in the form ax^2+bx+c