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sergeinik [125]
3 years ago
12

Explain the five generations of computer

Computers and Technology
2 answers:
liubo4ka [24]3 years ago
5 0

Answer:

1 First Generation

The period of first generation: 1946-1959. Vacuum tube based.

2 Second Generation

The period of second generation: 1959-1965. Transistor based.

3 Third Generation

The period of third generation: 1965-1971. Integrated Circuit based.

4 Fourth Generation

The period of fourth generation: 1971-1980. VLSI microprocessor based.

5 Fifth Generation

The period of fifth generation: 1980-onwards. ULSI microprocessor based.

IgorC [24]3 years ago
5 0

Answer:

First Generation of Computer (1940-1956)

The First Generations of computer used vacuum tubes in their hardware circuit and magnetic drum for their memory. They were gigantic in size and were kept in an enormous room.

Second Generation of Computers(1956-1963)

The Second generation of computers utilized “Transistor” instead of huge vacuum tubes. The transistor was designed and invented in 1947 by three physicians Bardeen, Brattain, and Shockley.

Third Generation of Computers(1964-1971)

The Third Generation of computer used Integrated Circuit (I.C) rather than vacuum tubes and transistors. Jack Kilby in 1958 created the Integrated Circuit. Number of other component and segments were used in a single silicon chip like Transistor, Resistor, and Capacitor and were called as “Semiconductors” which drastically improved and enhanced the speed, reliability, efficiency, and dependability.

Fourth Generations of Computers :: ( 1971-To Present Day)

The Fourth Generations of Computer used “Microprocessor” Instead of vacuum tubes and transistors. The PC that uses Microprocessor [CPU] is called as “Micro-Computers”. Microprocessor or Microchip are developed using Large scale Integration.

Fifth Generations of Computers (Present and Beyond)

The Fifth generation of computers are in a development face which uses AI (Artificial Intelligence).This types of computer will be very smart they will take their own decision.

Explanation:

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Explanation:

Solution:

The following reasons why Proponents  of IPs used IPV6 instead of IPv5​ is stated as follows:

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Develop a CPP program to test is an array conforms heap ordered binary tree. This program read data from cin (console) and gives
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Answer:

Following are the code to this question:

#include<iostream>//import header file

using namespace std;

int main()//defining main method

{

int ar[7];//defining 1_D array that stores value      

int i,x=0,l1=1,j; //defining integer variable

for(i=0;i<7;i++)//defining for loop for input value from user ends  

{

cout<<"Enter a Number: ";//print message

cin>>ar[i];//input value in array

if(l1<=2 && i>0)//using if block that checks the array values  

{

x++;//increment the value of x by 1  

}

if(l1>2 && i>0)//using if block that checks the array values  

{

l1=l1-2;//using l1 variable that decrases the l1 value by 2  

}

j=i-x;//using j variable that holds the index of the root of the subtree

if(i>0 && ar[j]>ar[i])// use if block that checks heap condition  

{

l1++; //increment the value of l1 variable

}

if(i>0 && ar[j]<ar[i])// using the if block that violate the heap rule  

{

cout<<ar[i]<<" "<<"Violate the heap";//print message with value

break;//using break keyword  

}

}

return 0;

}

Output:

1)

Enter a Number: -15

Enter a Number: -5

-5 Violate the heap

2)

Enter a Number: 45

Enter a Number: 0

Enter a Number: 55

55 Violate the heap

Explanation:

  • In the above-given C++ language code, an array "ar" and other integer variables " i,x,l1, j" is declared, in which "i" variable used in the loop for input values from the user end.
  • In this loop two, if block is defined, that checks the array values and in the first, if the block it will increment the value of x, and in the second if the block, it will decrease the l1 value by 2.
  • In the next step, j variable is used that is the index of the root of the subtree. In the next step, another if block is used, that checks heap condition, that increment the value of l1 variable. In the, if block it violate the heap rule and print its values.
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