We know that,
In a right-angled triangle,
Hypotenuse ² = Base ² + Height ²
1 – 10 ² = 6 ² + X ²
Or, X ² = 10 ² – 6 ²
Or, X ² = 100 – 36
Or, X ² = 64
Or, X = √ 64
Or, X = 8 Units
2– X² = 7² + 3²
Or, X² = 49 + 9
Or, X² = 58
Or, X = √58
Or, X = 7.61 Units ( Approx )
3 – 15 ² = EF ² + 9
Or, EF² = 15 ² – 9 ²
Or, EF ² = 225 – 91
Or, EF ² = 134
Or, EF = √ 134
Or, EF = 11.6 Inches ( Approx)
.II} 1 – Here the length of the ladder will be the hypotenuse.
Hence, Hypotenuse = 13 Metre
.Now, The vertical wall will be the height.
Hence, Height = 12 Metre
Distance of the foot of the ladder to the wall will be the base.
Let base be B.
Now, Hypotenuse ² = Base ² + Height ²
Or, 13² = B² + 12²
Or, B² = 13² – 12²
Or, B² = 169 – 144
Or, B² = 25
Or, B = √25
Or, B = 5 Metre
Hence, the distance of the foot of the ladder from the wall is 5 metre apart.
Pyramid Surface Area = (½ * Perimeter of Base * Slant Height) + Base Area
Answer: This is what I get.
Step-by-step explanation:
