Answer: -2
I hope this helps and may God bless you! Have a nice day, bye! :)
Answer:
Step-by-step explanation:
Quiana has 5 times more text messages from Yolanda than from Pierre, we also know that she actually has 30 text messages from Yolanda. In other words, 30 texts from Yolanda is 5 times more text messages than from Pierre.
Thus, if we call p the number of texts messages from Pierre we would have that
(since 30 texts from Yolanda is 5 times more than p, we can divide by 5 to find p)
And if we solve this equation we would get that Quiana has 6 text messages from Pierre
Multiply the first equation by 2
2x + 2y =30
now we’ll add the second equation to the first equation
2x + 2y =30
-2x+5y= -2
7y=28
divide by 7
y=4
now plug y back into the first equation
x + 4 = 15
subtract 4
x=11
-9-8(1+4h) = -17. We need to solve for h.
First, use the distributive property for 8(1+4h):
8(1+4h) = 8*1 + 8*4h = 8 + 32h
So -9-8(1+4h) = -17
-9 - (8+32h) = -17
-9 - 8 - 32h = -17
-17 - 32h = - 17
Add 17 on both sides to have the variables on a side and the numbers on the other:
-17 - 32h + 17 = -17 + 17
-32h = 0
divide both sides by -32 to get the variable h alone and its value on the other side:
(-32h)/-32 = 0/-32
h = 0.
So -9-8(1+4h) = -17 for h = 0.
You can recheck your answer (very important):
-9 - 8(1+4h) = -9 -8(1+4*0) = -9 - 8(1+0) = -9-8*1 = -9-8 = -17
The answer has been approved.
Hope this Helps! :)
Answer:
41.04 g/L
Step-by-step explanation:
The relationship is modeled by the following function:
S(t) = 500*e^(-0.25*t)
where t is time elapsed after the dilution begins (in hours) and S(t) the concentration of salt in the tank (in g/L)
Replacing with t = 10
S(t) = 500*e^(-0.25*10)
S(t) = 41.04 g/L
