Answer:
Plant B
Step-by-step explanation:
The only measure of variation we really need to check is the mean, or average, of tomatoes that each plant produced. This is because if Kathryn was a farmer, she would want a plant that on average, produces more tomatoes. For that reason, in this context, the mode, median and range are irrelevant. To find the mean of a data set, you simply divide the sum of all of the data by the number of data in the set. Therefore:
Mean of Plant A: (4 + 6 + 7 + 3 + 6 + 2 + 1 + 3 + 6 + 5) / 10 = 43 / 10 = 4.3
Mean of Plant B: (5 + 6 + 7 + 6 + 8 + 9 + 6 + 7 + 8 + 9) / 10 = 71 / 10 = 7.1
As you can see, the mean tomatoes Plant B produces is larger than that of Plant A, therefore, Kathryn should choose Plant B if she was a farmer.
Answer:
The answer is A. 7
Step-by-step explanation:
Answer:
well u have to give the picture
Step-by-step explanation:
Answer:
14
Step-by-step explanation: 2(4x+6)=
\,\,34-3x
34−3x
Since HJ is a midsegment, twice HJ is equal to EG.
8x+12=
8x+12=
\,\,34-3x
34−3x
Distribute.
8x+12=
8x+12=
\,\,-3x+34
−3x+34
Communicative property to change the order
\color{red}{+3x}\phantom{+12}\phantom{=}
+3x+12=
\,\,\color{red}{+3x}\phantom{+34}
+3x+34
+3x to both sides.
11x+12=
11x+12=
\,\,34
34
\phantom{11x}\color{red}{-12}\phantom{=}
11x−12=
\,\,\color{red}{-12}
−12
-12 to both sides.
11x=
11x=
\,\,22
22
\frac{11x}{11}=
11
11x
=
\,\,\frac{22}{11}
11
22
Divide both sides by 11
x=
x=
\,\,2
2
Value of x
HJ=
HJ=
\,\,4x+6
4x+6
Value of HJ
HJ=
HJ=
\,\,4(2)+6
4(2)+6
Plug in x.
HJ=
HJ=
\,\,8+6
8+6
Multiply.
HJ=
HJ=
\,\,14
14
Answer:
Step-by-step explanation:
Notice that we can get from the x-coordinate of A, 1, to the x-coordinte of A', -2, by subtracting 3 from the x-coordinate of A. More formaly:
Similarly, we can get from the y-coordinate of A, 5, to the y-coordinate of A', 3, by subtracting 2 from the y-coordinte of A. More formaly:
Now we now that to get to A' from A, we need to subtract 3 to the x-coordinate of A and subtract 2 to the y-coordinate. Knowing this, we can create the expression to translate any point of the polygon ABCD to create the polygon A'B'C'D':
