The answers are DNA and Nucleus
Androgenous behaviors is not solely the product of biological sexual
differences, such as the ability to bear children. It is also regarded as product of evolution
and natural selection where an individual may be androgynous, displaying feminine and
masculine characteristics or traits based on one’s gender identity and learned
gender role. This can be made possible through the ongoing social interactions
that individuals have with each other.
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The disorder is Emphysema.
It is a type of chronic obstructive pulmonary disease that presents as an abnormal and permanent enlargement of air spaces distal to the terminal bronchioles. It frequently occurs in association with obstructive problems and chronic bronchitis.
The answers would be:
Genotype Phenotype
Tt Tall stemmed
tt Short stemmed
Genotypic ratio : 2:2 or 1:1
Phenotypic ratio: 2:2 or 1:1
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<u>You can read on to see how this was done:</u>
Tall stems (T) are dominant to short stems (t).
First figure out the genotypes of the parents. We have a short-stemmed plant and a heterozygous long-stemmed plant cross.
For short stem to occur, you need 2 pairs of short alleles. So the first parent would have a genotype of tt.
Heterozygous long-stemmed means that the parent has one of each allele. So the genotype of the second parent would be, Tt.
Now we can make our Punnett Square.
tt x Tt
<u> t t </u>
<u>T | Tt | Tt</u>
<u>t | tt | tt</u>
Let's list down the genotypes and phenotypic results.
Genotype no. Phenotype
Tt 2 Tall stemmed
tt 2 Short stemmed
So from that we can answer the other questions:
Genotypic ratio : 2:2 or 1:1
Phenotypic ratio: 2:2 or 1:1