Answer:
Step-by-step explanation:
Given the populations P (in thousands) of a certain town in North Carolina, from 2006 through 2012 modeled by
P = 5.5e^kt,
If in 2008, the population was 7000. then;
at t = 2, P = 7000
7 = 5.5e^2k
7/5,5 = e^2k
1.2727= e^2k
Apply ln to both sides
ln 1.272 = lne^2k
ln 1.272= 2k
0.2411 = 2k
k = 0.2411/2
k = 0.1206 (to 4dp)
By 2018, the time t = 12 (2006-2018)
Substitute
P = 5.5e^(0.1206)(12)
P = 5.5e^(1.4468)
P = 5.5(4.2495)
P = 23.3722
P = 23372
Hence the population after 12 years is approx 23,372 populations
Answer:
The pattern is this: I create a function p(x) such that
p(1)=1
p(2)=1
p(3)=3
p(4)=4
p(5)=6
p(6)=7
p(7)=9
Therefore, trivially evaluating at x=8 gives:
p(8)= 420+(cos(15))^3 -(arccsc(0.304))^(e^56) + zeta(2)
Ok, I know this isn’t what you were looking for. Be careful, you must specify what type of pattern is needed, because the above satisfies the given constraints.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Multiply the equation by 2/g to get the t expression by itself. Then take the square root.
4(2/g) = t²
t = √(8/g)
t = 2√(2/g)
simplify the expression, <em> -4/7 + 2/7 x - 14 x + 4 / 7</em>
Answer : <em>-96x/7</em>
