For the numbers in form, convert to polar form:
By DeMoivre's theorem,
For the numbers already in polar form, DeMoivre's theorem can be applied directly:
At second glance, I think the 2s in the last two numbers should also be getting raised to the 3rd and 4th powers:
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Explanation:
Use the rational root theorem to determine this list of possible rational roots: 1, -1, 1/2, -1/2
Plug each possible root one at a time into the original expression given. If the simplified result is 0, then that possible root is an actual root.
If we tried say a = -1, then,
2a³-a²+a-2 = 2(-1)³-(-1)²+(-1)-2 = -6
The result is not zero, so a = -1 is not an actual root.
But if we tried say a = 1, then,
2a³-a²+a-2 = 2(1)³-1²+1-2 = 0
We get 0 so a = 1 is an actual root. I'll let you try the other values, but you should find that a = 1 is the only rational root.
Since a = 1 is a root, this makes (a-1) to be a factor.
From here, use either synthetic or polynomial long division to determine the other factor. Refer to the diagram below for each method.
Regardless of which method you pick, the quotient is 2a² + a + 2 which is the other factor needed. The remainder of 0 tells us we have (a-1) as a factor. For more information, check out the remainder theorem.
Answer:
Step-by-step explanation:
To solve, we need to find the y-intercept (b). In order to find the y-intercept, we can plug in the slope and the (x,y) coordinate pair given to us into the equation to solve for the y-intercept:
y=mx+b
4=(-7/-2)*-2+b
4=14/-2+b
4=-7+b
Add 7 to both sides
b=11
Therefore the equation is:
(note that the fraction is positive since the two negatives cancel out)