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andrew-mc [135]
3 years ago
13

Someone please help me I’ll give out brainliest please dont answer if you don’t know

Mathematics
2 answers:
Nat2105 [25]3 years ago
6 0
ANSWER

(n+2)(n+6)

EXPLANATION

n^2+8n+12
n^2= n•n
therefore (n+2)(n+6) is equal to n^2+8n+12


Soloha48 [4]3 years ago
5 0

Answer: 26 Fn²

Step-by-step explanation:

simple

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Given that S is the centroid of triangle MNO, find SQ.
DochEvi [55]

Answer:

First, we need to calculate for x. Since,

MP = PN

Thus,


3x-4 = x+4

2x = 8

x = 4


Next, we calculate for MS 

MS = 2x + 2 = 10


Since, MS = 2SQ

10 = 2SQ

Then,

SQ = 5 units


Therefore, the correct answer is B.





8 0
2 years ago
Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab
Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected,  and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, H_0 : \mu = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, H_1 : \mu < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

       T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = 738.44 hours

               s  = sample standard deviation = 38.2 hours

               n = sample size = 50

So, test statistics = \frac{738.44-750}{\frac{38.2}{\sqrt{50} } } ~ t_4_9

                            = -2.14

(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

6 0
3 years ago
The time between failures of a machine has an exponential distribution with parameter l. Suppose that the prior distribution for
ololo11 [35]
I'm like girl do you have plans. Can't keep my heart in your hands. She kicked me out I'm like vro.
6 0
3 years ago
The amount A of the radioactive element radium in a sample decays at a rate proportional to the amount of radium present. Given
slavikrds [6]

Answer:

a) \frac{dm}{dt} = -k\cdot m, b) m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }, c) m(t) = 10\cdot e^{-\frac{t}{2438.155} }, d) m(300) \approx 8.842\,g

Step-by-step explanation:

a) Let assume an initial mass m decaying at a constant rate k throughout time, the differential equation is:

\frac{dm}{dt} = -k\cdot m

b) The general solution is found after separating variables and integrating each sides:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }

Where \tau is the time constant and k = \frac{1}{\tau}

c) The time constant is:

\tau = \frac{1690\,yr}{\ln 2}

\tau = 2438.155\,yr

The particular solution of the differential equation is:

m(t) = 10\cdot e^{-\frac{t}{2438.155} }

d) The amount of radium after 300 years is:

m(300) \approx 8.842\,g

4 0
3 years ago
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Jared is taking inventory of the books in his school library. The graph shows the proportional relationship between the number o
KengaRu [80]

Answer:

No answer……

Step-by-step explanation:

No graph to go by.

7 0
2 years ago
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