Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.
Given:
Perimeter of the floor of a room = 18 metre
Height of the room = 3 metre
To find:
The area of 4 walls of the room.
Solution:
We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.
The curved surface area of the cuboid is

Where, h is height, l is length and b is breadth.
Perimeter of the rectangular base is 2(l+b). So,

Putting the given values, we get


Therefore, the area of 4 walls of the room is 54 sq. metres.
Okay, I'm pretty sure the answers are:
11) B
12) C
13) B
14) A
Answer:
it's a yes
Step-by-step explanation:
X/6 ≤ 30
to find the value of X we have to move the numerical to the other side
in this case the number is 1/6
X * 1/6 ≤ 30
so to balance the both side and get rid of the number on the left side we multiple with 6.
1/6*6 = 1 on the left side
30*6 = 180 on the right side
so the full equation will be
X * 1/6 * 6 ≤ 30 * 6
X * 1 ≤ 180
X ≤ 180
Let's go:
8)
Total of senior students = 38
Total of senior students that preferred evening classes: 7
7/38 = aproximately 0,18 or 18%
Alternative A)
9)
Imagine being sold 100 desserts. Of these 100 desserts, 75% até chocolate, meaning 75 of these desserts are chocolate. Of these 75, 23% contains nuts. So:
75 × 0,23 = 17,25 = aproximately 17,3%
Alternative C)
I hope I helped you.