It's the same angle which is 68
15 mi/h= 15mi/60 min= 1/4 (mi/min)
x is original speed (mi/min)
t is original time
x*t =260
(x+1/4)=5x/4 is new speed
t-20 - new time
(x+1/4)(t-20)=260
xt = (x+1/4)(t-20)
xt=xt + t/4 - 20x - 5
t/4=20x+5
t=80x +20
We can substitute t=80x +20 into equation x*t =260
x*(80x+20)=260
80x²+20x-260=0
4x²+x-13=0
D=b² - 4ac = 1+4*4*13= 209
x=(-1+/-√209)/2*4
x=1.68 mi/min
1.68mi/min * 60 min/1h≈100 mi/h
Check
260/100=2.6h time with old speed
260/(115)=2.26 h time with new speed
2.6-2.26 = 0.34 h difference between old and new time
0.34h*60min/1h≈20 min difference between old and new time in minutes
Answer:
Like terms are those terms whose variables and powers are same. For question no. 1
- 4p, 2p, p
- m^2 , 3m^2
- 5ac, 7ca
- 5v , 9v and 2wv , vw
- 6pq, 2qp, 3pq
- 3d, 2d
- 4mn, 2nm
- 4x^2y , x^2y
- 5ba, ab
Now for question no. 2
The like terms from the given term is C. 3ab, 2ba
If u have any confusion then u can ask hope it will help you
X = 4/5
y = 1/3
x+y = 4/5 + 1/3
x+y = 12/15 + 5/15
x+y = 17/15
Answer:
Here's what I get
Step-by-step explanation:
In each sum, the denominator of the second term is one greater than that in the first term.