(a)
You have a 10/26=5/13 chance of picking a red bulb with the first try. If you succeed, you'll have 25 bulbs remaining, 9 of which will be red, leading to a probability of 9/25 for the second pick to be red.
This means that the probability of picking two consecutive reds is
(b)
All the other answers will follow the same logic: you have again a 5/13 probability of picking a red bulb as the first bulb, then you'll have 25 remaining bulbs, 9 of which will be yellow. So, the probability of picking a red and then a yellow bulb is again
(c)
You'll have 9 yellow bulbs out of 26 with the first pick, and 10 red bulbs out of 25 with the second pick. So, the probability of picking a yellow and then a red is
(d)
Putting together (b) and (c), we can see that the probability of having a red and a yellow bulb is 9/65, no matter in which order the red and the yellow will appear.
Answer:
32
Step-by-step explanation:
x(48 - 2x) = 32
Hope it helps.
Answer:
Infinite solutions
Step-by-step explanation:
<u>Substitute -2x - 5 for y in 6x + 3y = -15 </u>
- <u></u>
- (simplify both sides of the equation
-
-
- (add 15 to both sides)
-
Therefore, the answer is infinite solutions.
The number of birdhouses is:
(9/10) : (1/20) = (9/1) * (20/10) = 9 * 2 = 18
Answer:
A. Miguel has the greatest spread.
B. Considering the middle 50% of the training time, the person with the least spread is Adam.
C. Miguel is inconsistent with the time set for training compared to that of Adam.
Step-by-step explanation:
The spread of a data shows the range of the data.
Using the range to determine the spread of the given data:
A. The range of the two persons can be determined by:
Range = highest value - lowest value
So that:
Adam's range = 106 - 91
= 15
Miguel's range = 105 - 86
= 19
Comparing the range of the two, Miguel has the greatest spread.
B. Considering the middle 50% of the training time;
Adam - 103 105 104 106 100
Miguel - 88 86 89 93 105
Adam's 50% range = 106 - 100
= 6
Miguel's 50% range = 105 - 86
= 19
Considering the middle 50% of the training time, the person with the least spread is Adam.
C. The answers to parts 2(a) and 2(b) shows that; there is a wide variation (much inconsistency) in the time that Miguel spend during training, but a minimum variation in the time spent by Adam during training.