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KIM [24]
2 years ago
13

What the solution for CED

Mathematics
2 answers:
ElenaW [278]2 years ago
7 0
Answer: 58 degrees
Explanation: 180-122=58
Alina [70]2 years ago
6 0

Answer:

Step-by-step explanation:

The two adjacent angles must have a sum of 180

CED=180-122

CED=58 degrees

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In an ice cream shop there is some money in a drawer. After 6 ice creams were sold, there were 70 euros left in the drawer. Afte
Verizon [17]

Answer: There were 40 euros in the drawer at the beginning.

Step-by-step explanation:

When we subtract 6 from 16, we get 10 more ice-creams were sold.

Similarly, we subtract 70 from 120, we get 50 euros was the total selling price of 10 ice-creams.

i.e. Selling price of 1 ice-cream = (50)÷10 =5 euros

Selling price of 6 ice-creams = 6 x 5 = 30 euros

Money in the drawer at the beginning = 70-30 = 40 euros

Hence, there were 40 euros in the drawer at the beginning.

7 0
3 years ago
A proportional relationship betweeof potatoes (x) and the price in dollars (y) is graphed, and the ordered pair (4, 3) is on the
CaHeK987 [17]
4/3 = 1/x.....4 lbs potatoes to $3 = 1 lb of potatoes to $x
cross multiply
(4)(x) = (3)(1)
4x = 3
x = 3/4
x = 0.75....so 1 lb of potatoes cost 75 cents


(8,6)...this means 8 lbs of potatoes cost $6
7 0
3 years ago
The perimeter of one face of a cube is 16cm. Calculate the volume of the cube.
erastova [34]

Answer:

4

Step-by-step explanation:

Perimeter equation: Length + Width * 2

so divide 2 by 16

which gives you 8 and minus that by its half so you get 4

4 0
2 years ago
What is the solution of the system of equations graphed?
DochEvi [55]

Answer:

A) (-3, 5)

General Formulas and Concepts:

<u>Algebra I</u>

  • Solving systems of equations by graphing

Step-by-step explanation:

The solution set to any systems of equations is where the 2 lines intersect. According to the graph, we see that the 2 lines intersect at (-3, 5). Therefore, our answer is A.

3 0
3 years ago
Read 2 more answers
PLZ HELP!!! Use limits to evaluate the integral.
Marrrta [24]

Split up the interval [0, 2] into <em>n</em> equally spaced subintervals:

\left[0,\dfrac2n\right],\left[\dfrac2n,\dfrac4n\right],\left[\dfrac4n,\dfrac6n\right],\ldots,\left[\dfrac{2(n-1)}n,2\right]

Let's use the right endpoints as our sampling points; they are given by the arithmetic sequence,

r_i=\dfrac{2i}n

where 1\le i\le n. Each interval has length \Delta x_i=\frac{2-0}n=\frac2n.

At these sampling points, the function takes on values of

f(r_i)=7{r_i}^3=7\left(\dfrac{2i}n\right)^3=\dfrac{56i^3}{n^3}

We approximate the integral with the Riemann sum:

\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{112}n\sum_{i=1}^ni^3

Recall that

\displaystyle\sum_{i=1}^ni^3=\frac{n^2(n+1)^2}4

so that the sum reduces to

\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{28n^2(n+1)^2}{n^4}

Take the limit as <em>n</em> approaches infinity, and the Riemann sum converges to the value of the integral:

\displaystyle\int_0^27x^3\,\mathrm dx=\lim_{n\to\infty}\frac{28n^2(n+1)^2}{n^4}=\boxed{28}

Just to check:

\displaystyle\int_0^27x^3\,\mathrm dx=\frac{7x^4}4\bigg|_0^2=\frac{7\cdot2^4}4=28

4 0
3 years ago
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