Ask question

Ask question

All categories

3 years ago

8

I have 4 factors.three of my factors are1,2,and 6 what is my fourth factor

1 answer:

oee [108]3 years ago

5 0

Answer:

I'd say the 4th factor is 3 assuming we are finding factors of 12. Hope this helps! :)

<h3>CloutAnswers</h3>

You might be interested in

Tomas makes a balloon sculptures at a circus. In 180 minutes, he uses 253 balloons to make 36 identical balloon sculptures.

Kipish [7]

$180\ minutes\ \ \ \rightarrow\ \ \ 252\ balloons\\\\1\ minute\ \ \ \rightarrow\ \ \ x\ balloons\\\\x\cdot 180=1\cdot 252\ \ \ \Rightarrow\ \ \ x= \frac{252}{180}= \frac{36\cdot7}{36\cdot5} = \frac{7}{5} =1.4\\\\Ans.\ \ 1.4\ balloons\ per\ one\ minute.\\\\-----------------\\\\ 1\ minute\ \ \ \rightarrow\ \ \ 1.4\ balloons\\\\10\ minutes\ \ \ \rightarrow\ \ \ x\ balloons\\\\x\cdot 1=10\cdot1.4\\\\x=14\\\\Ans.\ \ 14\ balloons\ per\ 10\ minutes.$

7 0

3 years ago

find the third,fifth and seventeenth terms of the sequence described by each explicit formula f(n)=8+3(n-1) and how you got it

alexira [117]

Answer:

Step-by-step explanation:

plug in 3 , 5 and 17 for n

8 + 3(3 -1) = 8 + 6 = 14

8 + 3(5-1) = 8 + 12 = 20

8 + 3(17-1) = 8 + 48 = 56

3 0

3 years ago

Suppose Jessica opens a savings account with $5000 that compounds interest daily. The APR at the time Jessica opens the account

IrinaK [193]

Hi there

1+0.035=(1+r/360)^360
Solve for r
R=(((1.035)^(1÷360)−1)×360)×100
R=3.44%

6 0

3 years ago

Solve for the distance between the points (4, 4) and (1, -3).

avanturin [10]

It should be 44 if it goes up to 1,10. If it is 1,5 it should end up as 44 As well. Sorry if I’m wrong. Please do not attack me.

4 0

3 years ago

For each of the following functions, determine if they are injective. Also determine if theyare surjective. Also determine if th

timurjin [86]

Answer:

Check below

Step-by-step explanation:

1. Definition for intervals

$(a,b)=\left \{ x\in\Re : a$

2. Functions

1) $\Re \rightarrow \Re \\ f(x)=x$

Let's perform graph tests.

That's an one to one, injective function. Look how any horizontal line touches that only once. Also, It's a surjective and a bijective one.

2) $\Re\geq0\rightarrow\Re , f(x)=x+1\\$

Injective, surjective and bijective.

Injective: a horizontal line crosses the graph in one point.

3) $f:\Re\geq 0\rightarrow\Re, f(x) = cos(x)$

The cosine function is not injective, bijective nor surjective.

4) $f:\Re\rightarrow\Re \:f(x)=ex$

Since e, is euler number it's a constant. It's also injective, surjective and bijective.

5) Quite unclear format

$6) \:f:\Re\rightarrow(0,\infty), f(x) =ex$

Despite the Restriction for the CoDomain, the function remains injective, surjective and therefore bijective.

$7) f:\Re\geq 0 \rightarrow \Re\geq0, f(x) =x^{4}$

Not injective nor surjective therefore not bijective too.

$8).f:\{-1,2,-3\}}\rightarrow \{1,4,9\}, f(x) =x^{2}$

$f(-1)=1, f(2)=4, f(-3)=9$

Injective (one to one), Surjective, and Bijective.

$10) f:\Re\geq 0\rightarrow [-1,1], f(x)= cos(x)\\-1=cos(x) \therefore x=\pi,3\pi,5\pi,etc.$

Surjective.

$11.f:R\geq 0[-1,1], f(x) = 0\\$

Surjective

12.f: US Citizens→Z, f(x) = the SSN of x.

General function

13.f: US Zip Codes→US States, f(x) = The state that x belongs to.

Surjective

7 0

2 years ago