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Nikitich [7]
3 years ago
10

In the year 1985, a house was valued at $120,000. By the year 2005, the value had appreciated exponentially to $145,000. What wa

s the annual growth rate between 1985 and 2005? (Round your answer to two decimal places.)
Assume that the value continued to grow by the same percentage. What was the value of the house in the year 2010? (Round your answer to the nearest dollar.)
Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
3 0

Answer:

The annual growth rate between 1985 and 2005 is 0.95%

The value of the house in the year 2010 is $152,018

Step-by-step explanation:

Let the annual growth rate = r

Value of the house in year 1985 = $120,000

Value of the house in year 2005 = $145,000

Time (t) = 2005 - 1985

            = 20 years

A = P (1 + r)^t

145000 = 120000 (1 + r) ^20

(1 +r)^20 = 145000 / 120000

(1 +r)^20= 1.2083

(1 +r)^20= (1.2083)^1/20

(1 +r)^20= 1.0095

r = 1.0095 - 1

r = 0.0095

r% = 0.0095 x 100

    = 0.95%

Value of the house in year 2010

=145000(1 + r)^5

=145000 (1 + 0.0095)^5

= 145000 x 1.0484

=$152,018

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A^k/b^k

Step-by-step explanation:

A/b^k=a^k/b^k

3 0
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Please help! Thank you!
KIM [24]
The correct answer is:  [B]:  " (2, 5) ".
__________________________________________
Given:
__________________________________________
  -5x + y = -5 ;
  -4x + 2y = 2 .
___________________________________________
  Consider the first equation:
___________________________
-5x + y = -5 ;  ↔ y + (-5x) = -5 ;

↔ y - 5x = -5 ;  Add "5x" to each side of the equation; to isolate "y" on one side of the equation; and to solve in terms of "y".
_____________________________________________
   y - 5x + 5x = -5 + 5x  

   y = -5 + 5x ;  ↔ y = 5x - 5 ;
____________________________________________
 Now, take our second equation:
______________________________
     -4x + 2y = 2 ; and plug in "(5x - 5)" for "y" ;  and solve for "x" :
_____________________________________________________
         -4x + 2(5x - 5) = 2 ; 
______________________________________________________
Note, 2(5x - 5) = 2(5x) - 2(5)  = 10x - 10 ;
__________________________________________
So:   -4x + 10x - 10 = 2 ;

On the left-hand side of the equation, combine the "like terms" ;

-4x +10x = 6x ;  and rewrite:

6x - 10 = 2  ;

Now, add "10" to each side of the equation:

6x - 10 + 10 = 2 + 10 ;

to get:

           6x = 12 ;  Now, divide EACH side of the equation by "6" ; to isolate "x" on one side of the equation; and to solve for "x" ; 

           6x/6 = 12 / 6 ;
 
                 x = 2 ;
_________________________________
Now, take our first given equation; and plug our solved value for "x" ; which is "2" ; and solve for "y" ;
_____________________________________
-5x + y = -5  ;

-5(2) + y = -5 ;

-10 + y = -5 ;  ↔
                              y - 10 = -5  ;

Add "10" to each side of the equation; to isolate "y" on one side of the equation; and to solve for "y" ;
     
         y - 10 + 10 = -5 + 10 ;

                   y = 5 .
_____________________________
So, we have, x = 2 ; and y = 5 .
____________________________
Now, let us check our work by plugging in "2" for "x" and "5" for "y" in BOTH the original first and second equations:
______________________________
first equation: 

-5x + y = -5 ;

-5(2) + 5 =? -5?

-10 + 5 =? -5 ? YES!
______________________
second equation:

-4x + 2y = 2 ;

-4(2) + 2(5) =? 2 ?

-8 + 10 =? 2 ?  Yes!
_______________________________________________________
So, the answer is: 
___________________________________________________________
          x = 2 , y = 5 ; or, "(2, 5)" ;  which is: "Answer choice: [B] " .
___________________________________________________________



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