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2 years ago

Please Help Me With This

Mathematics

1 answer:

IgorLugansk [536]2 years ago

4 0

What am i solving exactly?

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Select the statement that describes this expression: 10 + fraction 1 over 4x (5 + 3) − 3.

Tanya [424]

Answer:

Step-by-step explanation:

because i said so

5 0

1 year ago

Find the mass of the solid paraboloid Dequals={(r,thetaθ,z): 0less than or equals≤zless than or equals≤8181minus−r2, 0less th

Lubov Fominskaja [6]

Answer:

M = 5742π

Step-by-step explanation:

Given:-

- Find the mass of a solid with the density ( ρ ):

ρ ( r, θ , z ) = 1 + z / 81

- The solid is bounded by the planes:

0 ≤ z ≤ 81 - r^2

0 ≤ r ≤ 9

Find:-

Find the mass of the solid paraboloid

Solution:-

- The mass (M) of any solid body is given by the following triple integral formulation:

$M = \int \int \int {p ( r ,theta, z)} \, dV\\\\$

- We can write the above expression in cylindrical coordinates:

$M = \int\limits\int\limits_r\int\limits_z {r*p(r,theta,z)} \, dz.dr.dtheta \\\\M = \int\limits\int\limits_r\int\limits_z {r*[ 1 + \frac{z}{81}] } \, dz.dr.dtheta\\\\$

- Perform integration:

$M = \int\limits\int\limits_r{r*[ z + \frac{z^2}{162}] } \,|_0^8^1^-^r^2 dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{(81-r^2)^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{6561 -162r + r^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + 40.5 -r +\frac{r^2}{162} ] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{[ 121.5r-r^2 -\frac{161r^3}{162} ] } \, dr.dtheta\\\\$

$M = 2*\int\limits_0^\pi {[ 121.5r^2-r^3 -\frac{161r^4}{162} ] } |_0^6 \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 121.5(6)^2-(6)^3 -\frac{161(6)^4}{162} ] } \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 4375-216 -1288] } \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 2871] } \, dtheta\\\\M = 5742\pi kg$

- The mass evaluated is M = 5742π

8 0

2 years ago

What is the value of the expression 1/2(6x9x1)+15

Vanyuwa [196]

Answer:

the answer of the expression is 42

Step-by-step explanation:

PEMDAS parenthesis are first so we start out with 6x9x1 and the answer to that is 54, next is MULTIPLICATION so we take 1/2 times 52 which is 27 then next is ADD so we add 15 and the answer is 42

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3 years ago

jose spent 6 hours in school. each school period is 3/4 hour long. how many period did jose spend in school?

34kurt

Answer:

why are you asking me ask jose

6 0

2 years ago

I need a little help with this problem: 5k + 1 = 4k - 1

Varvara68 [4.7K]

5k-4k=-1+-1
k=-2, its all aboit rearranging the order of numders based on there like terms. If you need any more help ask.

8 0

2 years ago