A crow bar is a bar that help you lift thing up
(a) someone over 55
mean, mu = 22
standard deviation, sigma = 2
X=19
Z(X)=(X-mu)/sigma=(19-22)/2=-1.5
P(x>X)=1-P(x<X)=1-0.0668072=0.9331928
Therefore probability for a 55-year old to find a job in over 19 weeks is 0.9332
Assuming that each kind of seat is unnique and different from each other
( assume 4 kinds, premium, gold, silver, bronze, or premium, not premium, not premium, not premium)
so fraciton is parts out of whole so
1 out of 4 toal parts is 1/4