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Daniel [21]
3 years ago
15

Minim w Original price: $40; Markup: 15% The retail price is $

Mathematics
1 answer:
Grace [21]3 years ago
6 0
I was thinking it was maybe $34??? I’m super sorry if I’m wrong or if I’m too late!
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Power +, Inc. produces AA batteries used in remote-controlled toy cars. The mean life of these batteries follows the normal prob
Novay_Z [31]

Answer:

a) By the Central Limit Theorem, it is approximately normal.

b) The standard error of the distribution of the sample mean is 1.8333.

c) 0.1379 = 13.79% of the samples will have a mean useful life of more than 38 hours.

d) 0.7939 = 79.39% of the samples will have a mean useful life greater than 34.5 hours

e) 0.656 = 65.6% of the samples will have a mean useful life between 34.5 and 38 hours

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 36 hours and a standard deviation of 5.5 hours.

This means that \mu = 36, \sigma = 5.5

a. What can you say about the shape of the distribution of the sample mean?

By the Central Limit Theorem, it is approximately normal.

b. What is the standard error of the distribution of the sample mean? (Round your answer to 4 decimal places.)

Sample of 9 means that n = 9. So

s = \frac{\sigma}{\sqrt{n}} = \frac{5.5}{\sqrt{9}} = 1.8333

The standard error of the distribution of the sample mean is 1.8333.

c. What proportion of the samples will have a mean useful life of more than 38 hours?

This is 1 subtracted by the pvalue of Z when X = 38. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{38 - 36}{1.8333}

Z = 1.09

Z = 1.09 has a pvalue of 0.8621

1 - 0.8621 = 0.1379

0.1379 = 13.79% of the samples will have a mean useful life of more than 38 hours.

d. What proportion of the sample will have a mean useful life greater than 34.5 hours?

This is 1 subtracted by the pvalue of Z when X = 34.5. So

Z = \frac{X - \mu}{s}

Z = \frac{34.5 - 36}{1.8333}

Z = -0.82

Z = -0.82 has a pvalue of 0.2061.

1 - 0.2061 = 0.7939

0.7939 = 79.39% of the samples will have a mean useful life greater than 34.5 hours.

e. What proportion of the sample will have a mean useful life between 34.5 and 38 hours?

pvalue of Z when X = 38 subtracted by the pvalue of Z when X = 34.5. So

0.8621 - 0.2061 = 0.656

0.656 = 65.6% of the samples will have a mean useful life between 34.5 and 38 hours

4 0
3 years ago
4(n+2+2n+5+n+6)=-32 How do you show the problem?
yarga [219]

Answer:

n = -21/4 <em>or </em>-5.25

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Sherman goes golfing every 6^\text{th}6 th 6, start superscript, start text, t, h, end text, end superscript day and Brad goes g
nydimaria [60]

Answer:

In every 42 days,  Sherman and Brad will go golfing on the same day.

Step-by-step explanation:

Given:

Sherman goes golfing every 6th day.

Brad goes golfing every 7th day.

If they both went golfing today, we need to determine how many days unit they will go golfing on the same day again.

Solution:

In order to determine how many days unit Sherman and Brad will go golfing on the same day again, we will take least common multiple of 6 and 7.

To find least common multiple of 6 and 7, we will list out their multiples.

6=6,12,18,24,30,36,42

7=7,14,21,28,35,42

We find out that the least common multiple of 6 and 7 =42.

Thus, we can conclude that Sherman and Brad will go golfing on same days on every 42nd day after they meet..

7 0
3 years ago
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The tubs are similar in shape.
faltersainse [42]

Answer:

The tube are similar in shape.

The height of the small tub is 5  cm.

The volume of the small tube is 150  cm3.

The volume of the large tub is 500  cm3.

Work out the height of the large tub.

Give your answer correct to 3  significant figures.

Step-by-step explanation: Hope this help(:

3 0
10 months ago
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What is equivalent to 1 ½ meters
frosja888 [35]
1 5/10 meters is equivalent
6 0
2 years ago
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