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Ksenya-84 [330]
4 years ago
8

Alex purchased a 6-hour calling card. He has used t minutes of access time. Wrote an algebraic expression to represent how many

minutes he has remaining and identify the units for the expression.
Mathematics
2 answers:
Vadim26 [7]4 years ago
4 0
T= Mins
1 hour = 60 mins 
60 x 6 = 360
360 - T = x 
X= How many minutes he has remaining
mario62 [17]4 years ago
3 0

Answer: 360-t and the  units for the expression is minutes.

Step-by-step explanation:

Given : Alex purchased a 6-hour calling card.

Since , 1 hour = 60 minutes.

Then, 6\text{ hours}=6\times60=360\text{ minutes}

He has used t minutes of access time.

Then , the algebraic expression to represent the number of minutes he has remaining :_

360-t

The units for the expression is minutes.

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Answer:

1/2 mph??? if so 54 hours to travel 27 miles

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
A county in Alabama has a population of 90,000 people. It has an area of 800 mi2. How many people are there per square mile? A)
Zigmanuir [339]

Answer:

C) about 113

Step-by-step explanation:

"How many people are there per square mile?" means that we want a ratio with miles as denominator. In other words, to find the population density, we just need to divide the population by the land area (miles squared):

population-density=\frac{people}{land-area}

We know that the population of Alabama is 90,000 people and its land area is 800 miles squared, so people=90000 and land-area=800mi^{2}.

Replacing values:

population-density=\frac{people}{land-area}

population-density=\frac{90000}{800mi^{2}}

population-density=112.5

Which rounds to:

population-density=113

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5 0
4 years ago
How do you do this question?
Sergeeva-Olga [200]

Answer:

V = 2000r³/3

Step-by-step explanation:

We know that the base is a circular disk, so it creates a circle on the xy plane. It would be in the form x² + y² = r². In other words x² + y² = (5r)². Let's isolate y in this equation now:

x² + y² = (5r)²,

x² + y² = 25r²,

y² = 25r² - x²,

y = √25r² - x² ---- (1)

Now remember that parallel cross sections perpendicular to the base are squares. Therefore Area = length^2. The length will then be = 2√25r² - x² --- (2). Now we can evaluate the integral from -5r to 5r, of [ 2√25r² - x² ]² dx.

\int _{-5r}^{5r}\:\left[\:2\sqrt{\left(25r^2\:-\:x^2\right)}\:\right]\:^2\:dx\\=\int _{-5r}^{5r}4\left(25r^2-x^2\right)dx\\\\= 4\cdot \int _{-5r}^{5r}25r^2-x^2dx\\\\= 4\left(\int _{-5r}^{5r}25r^2dx-\int _{-5r}^{5r}x^2dx\right)\\\\= 4\left(250r^3-\frac{250r^3}{3}\right)\\\\= 4\cdot \frac{500r^3}{3}\\\\= \frac{2000r^3}{3}

As you can see, your exact solution would be, V = 2000r³/3. Hope that helps!

3 0
3 years ago
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