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Free_Kalibri [48]
3 years ago
6

A group of students must collect at least $120 to organize a science fair. They have already collected $30. Which graph best rep

resents all remaining amounts of money, in dollars, that the students should still collect to organize the science fair?
Number line graph with closed circle on 120 and shading to the right

Number line graph with closed circle on 90 and shading to the right.

Number line graph with closed circle on 150 and shading to the right

Number line graph with closed circle on 30 and shading to the right.

Mathematics
2 answers:
Bezzdna [24]3 years ago
8 0
Number line graph with closed circle on 30 and shading to the right
because you already have 30 dollars and they need at least 120 but if they get more then 120 they can still hold the science fair.
Nookie1986 [14]3 years ago
5 0

Answer:

The correct option is 2.

Step-by-step explanation:

It is given that a group of students must collect at least $120 to organize a science fair. They have already collected $30.  

Let the remaining amounts of money, in dollars, that the students should still collect to organize the science fair be x.

x+30\geq 120

Subtract 30 from both the sides.

x+30-30\geq 120-30

x\geq 90

It means the remaining amounts of money is greater than or equal to 90.

Therefore the number line graph with closed circle on 90 and shading to the right and option 2 is correct.

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Use the digits in the number 531,642 to write a number that is greater than and a number that is less than 531,642.
Nookie1986 [14]
642,531 is greater than 135,246
8 0
3 years ago
A quadrilateral has vertices A, B, C, and D. A line of reflection is drawn so that A is 6 units away from the line, B is 4 units
Kryger [21]

Answer:

The correct option is O B'

Step-by-step explanation:

We have a quadrilateral with vertices A, B, C and D. A line of reflection is drawn so that A is 6 units away from the line, B is 4 units away from the line, C is 7 units away from the line and D is 9 units away from the line.

Now we perform the reflection and we obtain a new quadrilateral A'B'C'D'.

In order to apply the reflection to the original quadrilateral ABCD, we perform the reflection to all of its points, particularly to its vertices.

Wherever we have a point X and a line of reflection L and we perform the reflection, the new point X' will keep its original distance from the line of reflection (this is an important concept in order to understand the exercise).

I will attach a drawing with an example.

Finally, we only have to look at the vertices and its original distances to answer the question.

The vertice that is closest to the line of reflection is B (the distance is 4 units). We answer O B'

8 0
3 years ago
Choose the solution(s) of the following system of equations x2 + y2 = 6 x2 – y = 6
ElenaW [278]
<h2>Answer</h2>

x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1

Or as ordered pairs: (\sqrt{6} ,0),(-\sqrt{6} ,0),(\sqrt{5} ,-1),(-\sqrt{5} ,-1)

<h2>Explanation</h2>

Lets solve our system of equations  step by step

x^2+y^2=6 equation (1)

x^2-y=6 equation (2)

1. Solve for x^2 in equation (2)

x^2-y=6

x^2=6+y equation (3)

2. Replace equation (3) in equation (1) and solve for y

x^2+y^2=6

6+y+y^2=6

y^2+y=0

y(y+1)=0

y=0 or y=-1

3. Replace the values of y in equation (3) and solve for x

- For y=0

x^2=6+y

x^2=6

x=\sqrt{6} or x=-\sqrt{6}

- For y=-1

x^2=6+y

x^2=6-1

x^2=5

x=\sqrt{5} or x=-\sqrt{5}

So, the solutions of our system of equation are:

x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1

6 0
2 years ago
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Answer:

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Step-by-step explanation:

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32x = -4

32x/32

x

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Explanation:
8 0
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