Answer:
we determine that none of the ordered pair is a solution of 
as none of the ordered pairs satisfy the equation.
Step-by-step explanation:
Considering the equation
- Putting (-5,2) in the equation
∵ L.H.S ≠ R.H.S
FALSE
- Putting (0,-5) in the equation
∵ L.H.S ≠ R.H.S
FALSE
- Putting (5,1) in the equation
∵ L.H.S ≠ R.H.S
FALSE
- Putting (7,5) in the equation
∵ L.H.S ≠ R.H.S
FALSE
From the above calculations, we determine that none of the ordered pair is a solution of as none of the ordered pairs satisfy the equation.
Actually Welcome to the Concept of the Factorisation.
Since here both are the roots of the quadratic equation in the factor form, hence
equate them to zero, to get the value of x
hence,
2x-9 = 0
===> x = 9/2
and
3x+5=0
===> x = -5/3
If A = L x W. . . Then L = A/W
Might be terribly wrong since it's been a while that I've done fractions, but I got -11/20. Hope this helps!!!
