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Evgen [1.6K]
3 years ago
6

Solve sin4x cosx-sinx cos4x = sqrt(2)/2 for [0, 2pi)

Mathematics
1 answer:
natita [175]3 years ago
4 0

Answer:

x = π/12, π/4, 3π/4, 11π/12, 17π/12, 19π/12

Step-by-step explanation:

sin(4x) cos x − sin x cos(4x) = √2 / 2

Use angle difference formula.

sin(4x − x) = √2 / 2

sin(3x) = √2 / 2

3x = π/4 + 2kπ, 3π/4 + 2kπ

x = π/12 + 2kπ/3, π/4 + 2kπ/3

x = π/12, π/4, 3π/4, 11π/12, 17π/12, 19π/12

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<em>P V</em> = <em>n R T</em>

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<em>V</em> = volume

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<em>T</em> = temperature

If both <em>n</em> and <em>T</em> are fixed, then <em>n R T</em> is a constant quantity, so for two pressure-volume pairs (<em>P</em>₁, <em>V</em>₁) and (<em>P</em>₂, <em>V</em>₂), you have

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Solve for <em>V</em>₂ :

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CDuc has a trapezoid shaped section of his yard fenced off for his pets. The lengths of the parallel sides of the trapezoid are
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I hope this helps you



Area =(8+14).4/2


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[PICTURE ATTACHED] HHHHEEEELLLPPP!
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Step-by-step explanation:

The Same= Free points

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Hello kiddio lets figure this out!

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Have a nice day
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