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Marina86 [1]
3 years ago
10

HELP WILL GRIVE BRAIN 100 POINTS PLEASE ANSWER ALL 5

Mathematics
2 answers:
Stels [109]3 years ago
7 0

Answer:

1. The sum of 4 and x is 7, and to isolate the variable, you move the 4 to the other side and the equation will change into x=7-4, giving us x = 3

2. To solve this inequality, you must isolate the variable x by moving -9 to the other side. To do this, you have to divide 27 by -9, and this causes the direction of the inequality sign to change. After you divide, the inequality changes to this: x<-3

3. since there are no negative numbers involved in this inequality, you divide 3 by 1/4 (or multiply it by 4) to isolate x. this gives us x <= -12

4. To solve this algebraic equation, you must isolate the variable 3x. To do this, you must move -9 to the other side of the equation by adding 9 to the 6. this gives us 3x=15 and x = 5

5. To put x by itself, you subtract 1 by 4, giving you x<-3

nika2105 [10]3 years ago
3 0
I am not sure sorry,Why? Did you search up how to take a screen shot lol
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(6/13)/(6/12)= (6/13)*(12/6)= 12/13   
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Clarinex is a drug used to treat asthma. In clinical tests of this drug, 1655 patients were treated with 5- mg doses of Clarinex
bagirrra123 [75]

Answer:

z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363  

p_v =P(z>3.363)=0.00039  

So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

Step-by-step explanation:

Data given and notation

n=1655 represent the random sample taken

\hat p=0.021 estimated proportion of interest

p_o=0.012 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that true proportions is higher than 0.012.:  

Null hypothesis:p \leq 0.012  

Alternative hypothesis:p > 0.012  

When we conduct a proportion test we need to use the z statisitic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>3.363)=0.00039  

So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

3 0
3 years ago
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