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Alenkasestr [34]
3 years ago
12

The formula for the area of a triangle is A=1/2bh

Mathematics
1 answer:
Molodets [167]3 years ago
6 0

Answer:

h=\dfrac{2A}{b}

Step-by-step explanation:

The formula for the area of a triangle is given by :

A=\dfrac{1}{2}bh

Where

b is base and h is height

We need to rearrange the formula to solve for height h.

Cross multiply the given relation

2A=bh

Dividing both sides by b.

\dfrac{2A}{b}=\dfrac{bh}{b}\\\\h=\dfrac{2A}{b}

So, the formula for the height of the triangle is \dfrac{2A}{b}.

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Norma-Jean [14]

Answer:

F=15

Step-by-step explanation:

3 0
3 years ago
Suppose f(x)=2x−5. Find the value of f(3)<br><br> can someone please help me with this?
dmitriy555 [2]

f(3) = 1

substitute x = 3 into f(x)

f(3) = (2 × 3) - 5 = 6 - 5 = 1


3 0
3 years ago
=
slamgirl [31]

Answer:D

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 8.5%/100 = 0.085 per year

putting time into years for simplicity

6 months ÷ 12 months/year = 0.5 years

then, solving our equation

I = 10000 × 0.085 × 0.5 = 425

I = $ 425.00

on a principal of $ 10,000.00

at a rate of 8.5% per year

for 0.5 years (6 months) is $ 425.00

3 0
2 years ago
Math im soooooooooooooo baaaaaaaaaaaadddddddddddddd
storchak [24]

Answer:

The correct answer is A, 73

Step-by-step explanation:

First we have to arrange the whole numbers in ascending order. i-e from smallest to largest. Showing it as follows:

53 54 59 62 64 65 66 68 70 71 75 78 79 79 83 83 86 90 91 94                

Now we would find the median by taking the middle number. But this series consists of even numbers. There are 20 numbers. So we will take the middle two numbers and find their average like follows:

71 + 75 = 146/2  = 73

The answer is 73

8 0
3 years ago
Read 2 more answers
You are given the parametric equations x=2cos(θ),y=sin(2θ). (a) List all of the points (x,y) where the tangent line is horizonta
vladimir1956 [14]

Answer:

The solutions listed from the smallest to the greatest are:

x:  -\sqrt{2}   -\sqrt{2}  \sqrt{2}  \sqrt{2}

y:      -1         1     -1     1

Step-by-step explanation:

The slope of the tangent line at a point of the curve is:

m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }

m = -\frac{\cos 2\theta}{\sin \theta}

The tangent line is horizontal when m = 0. Then:

\cos 2\theta = 0

2\theta = \cos^{-1}0

\theta = \frac{1}{2}\cdot \cos^{-1} 0

\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right), for all i \in \mathbb{N}_{O}

\theta = \frac{\pi}{4} + i\cdot \frac{\pi}{2}, for all i \in \mathbb{N}_{O}

The first four solutions are:

x:   \sqrt{2}   -\sqrt{2}  -\sqrt{2}  \sqrt{2}

y:     1        -1        1     -1

The solutions listed from the smallest to the greatest are:

x:  -\sqrt{2}   -\sqrt{2}  \sqrt{2}  \sqrt{2}

y:      -1         1     -1     1

6 0
3 years ago
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