Answer:
A "skewed right" distribution is one in which the tail is on the right side. A "skewed left" distribution is one in which the tail is on the left side. The above histogram is for a distribution that is skewed right. ... Be that as it may, several "typical value" metrics are often used for skewed distributions.
Discussion of Skewness: The above is a histogram of the SUNSPOT.DAT data set. A ...
Some Causes for Skewed Data: Skewed data often occur due to lower or upper
Answer:
(A)
Step-by-step explanation:
To be honest, since all of them are different, as long as you get the first one right, you will get the others right. A is your answer, for the following reasons:
Reflexive Property: The Reflexive property states that the mirrored version of itself will always be congruent with itself. Generally, to make it easier, they will write it opposite (as they did in the given proof):
<em>line</em> AC ≅ <em>line</em> CA
~
Answer:
That's the graph for the function f(x)= -1/2 x^2 + 7
The vertex is f(0) = 7
Answer:
$3.94
Step-by-step explanation:
$30.42 + $9.89 + $5.75 = £46.06
$50.00 - $46.06 = $3.94
Answer:
Option A. one rectangle and two triangles
Option E. one triangle and one trapezoid
Step-by-step explanation:
step 1
we know that
The area of the polygon can be decomposed into one rectangle and two triangles
see the attached figure N 1
therefore
Te area of the composite figure is equal to the area of one rectangle plus the area of two triangles
so
![A=(8)(4)+2[\frac{1}{2}((8)(4)]=32+32=64\ yd^2](https://tex.z-dn.net/?f=A%3D%288%29%284%29%2B2%5B%5Cfrac%7B1%7D%7B2%7D%28%288%29%284%29%5D%3D32%2B32%3D64%5C%20yd%5E2)
step 2
we know that
The area of the polygon can be decomposed into one triangle and one trapezoid
see the attached figure N 2
therefore
Te area of the composite figure is equal to the area of one triangle plus the area of one trapezoid
so
