Let A( t , f( t ) ) be the point(s) at which the graph of the function has a horizontal tangent => f ' ( t ) = 0.
But, f ' ( x ) = [ ( x^2 ) ' * ( x - 1 ) - ( x^2 ) * ( x - 1 )' ] / ( x - 1 )^2 =>
f ' ( x ) = [ 2x( x - 1 ) - ( x^2 ) * 1 ] / ( x - 1 )^2 => f ' ( x ) = ( x^2 - 2x ) / ( x - 1 )^2;
f ' ( t ) = 0 <=> t^2 - 2t = 0 <=> t * ( t - 2 ) = 0 <=> t = 0 or t = 2 => f ( 0 ) = 0; f ( 2 ) = 4 => A 1 ( 0 , 0 ) and A 2 ( 2 , 4 ).
Answer:
(0,0)
Step-by-step explanation:
x value of vertex = -b/2a
ax^2+bx+c
-2x^2+0x+0 sinc you have no value of b & c in your quadratic function
-b = 0
2a = (2)(-2)
-b/2a = (0/-4) = 0
x value of the vertex = 0
plug 0 in for all values of x in the function to find y coordinate value
-2(0)^2 = 0
(x,y) = (0,0)
Answer:
Chris earned $ 43,344 each year
Monthly Chris earns $ 3,612
Step-by-step explanation:
If you earn a fixed amount of money each month, for 2 years and one year you have 12 months, then 2 years equals 24 months.
To know how much you earn each month we divide the total amount earned in the two years between 24 months
I = $ 86,688 / 24
I = $ 3,612
Monthly Chris earns $ 3,612
To calculate what he earned each year we divided $ 86,688 / 2
I = $ 86,688 / 2
I = $ 43,344
Chris earned $ 43,344 each year
8t+32 is one expression equivalent to that.
Divide the total by the quantity of numbers:
852/3 = 284
Because there are an odd quantity of numbers (3) the answer is the middle number.
The answer is 284
