Answer:
The answer is "Option A"
Explanation:
In the OOPs programming language, the class and object concept is used, in which class is a collection of data members, and member function and object is known as real-time entity. In the class when the main method is created, so inside this method class object is created that's why the answer to this question is true.
Answer:
ssume that,
Maximum “students” count can be 10.
*Driver Class*
*Solution class*
import java.util.*;
class Student {
private String name;
private int rollNo;
public String getName() {}
public void setName(String name) {}
public int getRollNo() {}
public void setRollNo(int rollNo) {}
};
class ClassRoom {
private int i;
private Student[] students;
public void addStudent(String name, int rollNo) {}
public Student[] getAllStudents() {}
};
Answer: (B) Branch cache
Explanation:
The branch cache is the process of cache the data from the given file and the wen server on the wide area network. In the WAN connection, the branch code is the type of functionality which basically allow the window to providing the remote user support in the network. The branch cache basically work on the two mode that are:
- The distributed mode
- The host mode
The branch cache is the one of the technology that intend the cache data for reducing the network traffic in the wide are network.
Therefore, Option (B) is correct.
Answer:
#include <stdio.h>
#include <ctype.h>
void printHistogram(int counters[]) {
int largest = 0;
int row,i;
for (i = 0; i < 26; i++) {
if (counters[i] > largest) {
largest = counters[i];
}
}
for (row = largest; row > 0; row--) {
for (i = 0; i < 26; i++) {
if (counters[i] >= row) {
putchar(254);
}
else {
putchar(32);
}
putchar(32);
}
putchar('\n');
}
for (i = 0; i < 26; i++) {
putchar('a' + i);
putchar(32);
}
}
int main() {
int counters[26] = { 0 };
int i;
char c;
FILE* f;
fopen_s(&f, "story.txt", "r");
while (!feof(f)) {
c = tolower(fgetc(f));
if (c >= 'a' && c <= 'z') {
counters[c-'a']++;
}
}
for (i = 0; i < 26; i++) {
printf("%c was used %d times.\n", 'a'+i, counters[i]);
}
printf("\nHere is a histogram:\n");
printHistogram(counters);
}
