When two line cross each othe vertical angles are formed
Answer:
28
Step-by-step explanation:
Given : f(x)= 3|x-2| -5
f(x) is translated 3 units down and 4 units to the left
If any function is translated down then we subtract the units at the end
If any function is translated left then we add the units with x inside the absolute sign
f(x)= 3|x-2| -5
f(x) is translated 3 units down
subtract 3 at the end, so f(x) becomes
f(x)= 3|x-2| -5 -3
f(x) is translated 4 units to the left
Add 4 with x inside the absolute sign, f(x) becomes
f(x)= 3|x-2 + 4| -5 -3
We simplify it and replace f(x) by g(x)
g(x) = 3|x + 2| - 8
a= 3, h = -2 , k = -8
I was confused at first until I realized that you'd shared not one, not two, but three questions in one post. would you please post just one question at a time to avoid this.
I'll focus on your second question only: Solve <span>3 + |2x - 4| = 15.
Subtr. 3 from both sides. Result: |2x - 4| = 12
Divide all terms by 2, to reduce: |x - 2| = 6
Case 1: x-2 is already +, so we don't need | |:
x - 2 = 6 => x = 8 (first answer)
Case 2: x-2 is negative, so |2x-4| = -(2x-4) = 6
Then -2x + 8 = 6. Subtr. 8 from both sides: -2x = -2
Div both sides by -2: x = 1 (second answer)
Be sure to check these results by subst. them into the original equation.
Please post your other questions separately. Thanks and good luck!
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