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3 years ago

Word problems Patterns complete the patterns : 5 , 7 , 10 , 14 , ... need help

Mathematics

2 answers:

alexandr402 [8]3 years ago

8 0

Answer:

in the same way

dlinn [17]3 years ago

6 0

Answer:19,25,32

Step-by-step explanation:14+5=19 19+6=25 25+7=32

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How many 2/3s are in 6 please answer

san4es73 [151]

6/ 2/3

is equal to (6 x 3) / 2 = 3 x 3 = 9

4 0

4 years ago

Write the equation x + 3y = -4 in slope-intercept form, and then find the slope and y-intercept.

katrin2010 [14]

Answer with step by step explanation

To find the equation of the line from the given equation, you have to make y as the subject in the equation.

Let us find now.

x + 3y = -4

3y = -4 - x

3y = -x - 4

Divide the whole equation by 3.

y = -x/3 - 4/3

Therefore, the equation of the line is:

y = -x/3 - 4/3

And now we have to find the slope and the y - intercept of the line.

That is, we have to find the m & c of y = m x + c.

Here,

m ⇒ slope

c ⇒ y - intercept

So, to find it we have to find the values which were replaced with m & c.

Let us find now.

y = m x + c

y = -x/3 - 4/3

Now it is clear that, -1/3 & -4/3 are replaced with m & c respectively.

Therefore,

slope ⇒ -1/3

y - intercept ⇒ -4/3

4 0

2 years ago

Consider the following. f(x) = x5 − x3 + 6, −1 ≤ x ≤ 1 (a) Use a graph to find the absolute maximum and minimum values of the fu

kykrilka [37]

ANSWER

See below

EXPLANATION

Part a)

The given function is

$f(x) = {x}^{5} - {x}^{3} + 6$

From the graph, we can observe that, the absolute maximum occurs at (-0.7746,6.1859) and the absolute minimum occurs at (0.7746,5.8141).

b) Using calculus, we find the first derivative of the given function.

$f'(x) = 5 {x}^{4} - 3 {x}^{2}$

At turning point f'(x)=0.

$5 {x}^{4} - 3 {x}^{2} = 0$

This implies that,

${x}^{2} (5 {x}^{2} - 3) = 0$

${x}^{2} = 0 \: or \: 5 {x}^{2} - 3 = 0$

$x = - \frac{ \sqrt{15} }{5} \: or \: x = 0 \: \: or \: x =\frac{ \sqrt{15} }{5}$

We plug this values into the original function to obtain the y-values of the turning points

$( - \frac{ \sqrt{15} }{5} , \frac{1}{125} ( 6 \sqrt{15} +750)) \:and \: (0, - 6) \: and\: ( \frac{ \sqrt{15} }{5} , \frac{1}{125} ( - 6 \sqrt{15} +750))$

We now use the second derivative test to determine the absolute maximum minimum on the interval [-1,1]

$f''(x) = 20 {x}^{3} - 6x$

$f''( - \frac{ \sqrt{15} }{5} ) \: < \: 0$

Hence

$( - \frac{ \sqrt{15} }{5} , \frac{1}{125} ( 6 \sqrt{15} + 750))$

is a maximum point.

$f''( \frac{ \sqrt{15} }{5} ) \: > \: 0$

Hence

$( \frac{ \sqrt{15} }{5} , \frac{1}{125} (- 6 \sqrt{15} + 750))$

is a minimum point.

$f''(0) \: =\: 0$

Hence (0,-6) is a point of inflexion

4 0

3 years ago

Which two values of x are roots of the polynomial below? 4x^2 - 6x + 1

Stella [2.4K]

Answer:

-2

Step-by-step explanation:

6 0

4 years ago

What is the percent for;

lesantik [10]

Answer:

Step-by-step explanation:

First you have to make it into a fraction, then multiply it by 100 :

Q1.

$0.47 = \frac{47}{100}$

$\frac{47}{100} \times 100 = 47$

Q2.

$0.98 = \frac{98}{100}$

$\frac{98}{100} \times 100 = 98$

Q3.

$0.25 = \frac{25}{100}$

$\frac{25}{100} \times 100 = 25$

8 0

3 years ago