Using a binomial distribution considering there's a 30% chance it will rain on any of the three days:
<span>The probability of it raining on 0 days is (1)(0.7)(0.7)(0.7) = 34.3%. </span>
<span>The probability of it raining on 1 day is (3)(0.3)(0.7)(0.7) = 44.1%. </span>
<span>The probability of it raining on 2 days is (3)(0.3)(0.3)(0.7) = 18.9%. </span>
<span>The probability of it raining on 3 days is (1)(0.3)(0.3)(0.3) = 2.7%. </span>
<span>There's a 65.7% chance that it will rain at least once over the three-day period.</span>
Answer:
b
Step-by-step explanation:
Answer is 9(-2)=-18 but that choice doesn't appear in your list of answers
6 and 17
m+m+1=33
2m=32
m=16
