Answer: try taking it to your media center for help or maybe try connecting to different wifi
Explanation:
Answer:
See explaination for the program code
Explanation:
The code below
Pseudo-code:
//each item ai is used at most once
isSubsetSum(A[],n,t)//takes array of items of size n, and sum t
{
boolean subset[n+1][t+1];//creating a boolean mtraix
for i=1 to n+1
subset[i][1] = true; //initially setting all first column values as true
for i = 2 to t+1
subset[1][i] = false; //initialy setting all first row values as false
for i=2 to n
{
for j=2 to t
{
if(j<A[i-1])
subset[i][j] = subset[i-1][j];
if (j >= A[i-1])
subset[i][j] = subset[i-1][j] ||
subset[i - 1][j-set[i-1]];
}
}
//returns true if there is a subset with given sum t
//other wise returns false
return subset[n][t];
}
Recurrence relation:
T(n) =T(n-1)+ t//here t is runtime of inner loop, and innner loop will run n times
T(1)=1
solving recurrence:
T(n)=T(n-1)+t
T(n)=T(n-2)+t+t
T(n)=T(n-2)+2t
T(n)=T(n-3)+3t
,,
,
T(n)=T(n-n-1)+(n-1)t
T(n)=T(1)+(n-1)t
T(n)=1+(n-1)t = O(nt)
//so complexity is :O(nt)//where n is number of element, t is given sum
Answer:
-
= 1
= 1
Explanation:
Argon atom has atomic number 18. Then, it has 18 protons and 18 electrons.
To determine the quantum numbers you must do the electron configuration.
Aufbau's principle is a mnemonic rule to remember the rank of the orbitals in increasing order of energy.
The rank of energy is:
1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s < 4d < 5p < 6s < 4f < 5d < 6p < 7s < 5f < 6d < 7d
You must fill the orbitals in order until you have 18 electrons:
- 1s² 2s² 2p⁶ 3s² 3p⁶ : 2 + 2 + 6 + 2 + 6 = 18 electrons.
The last electron is in the 3p orbital.
The quantum numbers associated with the 3p orbitals are:
- = 1 (orbitals s correspond to = 0, orbitals p correspond to = 1, orbitals d, correspond to = 2 , and orbitals f correspond to = 3)
- can be -1, 0, or 1 (from - to + )
- the fourth quantum number, the spin can be +1/2 or -1/2
Thus, the six possibilities for the last six electrons are:
- (3, 1, -1 +1/2)
- (3, 1, -1, -1/2)
- (3, 1, 0, +1/2)
- (3, 1, 0, -1/2)
- (3, 1, 1, +1/2)
- (3, 1, 1, -1/2)
Hence, the correct choice is:
- = 1
- = 1
Raymond should compress the files, and then at the very least ask what would be the appropriate time to email the attachment. It is important to practice good etiquette when using email. If you are sending an email that has attachments, always make sure to mention it in the body of the email. Raymond should also ZIP or compress his large attachments before sending them. This will make them easier to send.
