Answer:
(24y^3x-20y^5x^2)/(-3y^5x^2)
= y^3x(24-20y^2x))/(-3y^5x^2)
=(24-20y^2x)/(-3y^2x)
=(24/(-3y^2x))-((20y^2x)/(-3y^2x))
=(-8/y^2x)-(-20/3)
=-8/y^2x + 20/3
Because they will always be divisible by 5
Answer:
64
Step-by-step explanation:
First of all substitute the values to where ever you see their corresponding variables to make them multiply.
x = 9
y = 3
z = 2
so we get
8x as 8(9),
7z as 7(2)
2y as 2(3)
then the it's will be
8(9) - 7(2) + 2(3)
which is
72 - 14 + 6
finally we get
64
