The limit of the function <span>( sin3x sin5x ) / x^2 as x approaches zero is evaulated by substituting the function by zero. Since the answer is zero / zero which is indeterminate. Using L'hopitals rule, we derive separately the numerator and the denominator. we all know that sin 5x and sin 3x are equal to zero. Upon teh first derivative, the answer is still zero / zero. We derive further until the function has a denominator of 2 and a numerator still equal to zero. Since the answer is now zero/ 2 or zero not zero/zero, the limit then is equal to zero.</span>
I do not the question. Please explain
Answer:
the answer is (2,-6)
Step-by-step explanation:
I would estimate around 6 because say it was 6.5 and 3 then it would around the square root of like 31 and that is rounding down a lot so we would bump it up to somewhenre around 35 so the side would be around 5.8-6
