Its 54 your welcome because i did this from khan and i got it 54 right so its 54

Write down in terms of n, an expression for the nth term of the following sequences 2,8,18,32,50,

Art [367]

Answer:

198

Step-by-step explanation:

2+6=8+10=18+14=32+18=50+22=72+26=96+30=126+34=160+38=198

4 0

3 years ago

Is 5/4 greater than , less than , or equal to the square root of 2

victus00 [196]

Answer:

less than

Step-by-step explanation:

the square root of 2 is 4 and 5/4 is 1.25

8 0

3 years ago

Use the given pair of functions to find and simplify expressions for the following functions and state the domain of each using

Tamiku [17]

Answer:

Given functions,

$f(x) = 3 - x^2$

$g(x) = \sqrt{x}+1$

Since, by the compositions of functions,

1. (g◦f)(x) = g(f(x))

$=g(3-x^2)$

$=\sqrt{3-x^2}+1$

Since, (g◦f) is defined,

If 3 - x² ≥ 0

⇒ 3 ≥ x²

⇒ -√3 ≤ x ≤ √3

Thus, Domain = [-√3, √3]

2. (f◦g)(x) = f(g(x))

$=f(\sqrt{x}+1)$

$=3-(\sqrt{x}+1)^2$

Since, (g◦f) is defined,

If x ≥ 0

Thus, Domain = [0, ∞)

3. (f◦f)(x) = f(f(x))

$=f(3-x^2)$

$=3-(3-x^2)^2$

$=3-9-x^4+6x^2$

$=-6+6x^2-x^4$

Since, (f◦f) is a polynomial,

We know that,

A polynomial is defined for all real value of x,

Thus, Domain = (-∞, ∞)

8 0

3 years ago

od odsetek dopisywanych w banku nalezy zapłacić podatek w wysokości 19%. Obliczamy go w następujący sposób: zaokrąglamy kwotę zy

Ivan

Answer:

Pretty sure its 100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000

Step-by-step explanation:

This question makes no sense so my answer makes no sense.

6 0

3 years ago

Help me please ❤️❤️❤️❤️

melomori [17]

In a quadratic function, $f(x)= ax^2+bx+c$ the leading coefficient is $a$ , i.e. the coefficient of $x^2$ , and the constant term is $c$ , i.e. the coefficient without any power of $x$ .

So, if you want leading coefficient 2 and constant term -3, your function needs to be like

$f(x)=2x^2+bx-3$

for any value of $b$ . Among your options:

The first is not a quadratic (it starts with $x^3$ )
The second has leading term -3 and constant term 2
The third is not a quadratic (same as the first)
The last is correct.

4 0

3 years ago