Answer:
see below
Step-by-step explanation:
The graph has two parts. There is one line for x < 2. It has a slope of 1 and a y-intercept of 0.
The line for x > 2 is the horizontal line x=2.
The point at x=2 is not defined by the function you have posted here, so there is a "hole" in the graph at that point.
Answer:
g(x) = (1/6)(x +7)^2 -8
Step-by-step explanation:
The transformation ...
g(x) = a·f(x -h) +k
represents vertical scaling by a factor of 'a', right shift by h units, and up shift by k units. You want the function g(x) for f(x) = x^2, a = 1/6, h = -7, and k = -8. Those transformations give you ...
g(x) = (1/6)(x +7)^2 -8
