4.

Half of a sphere is stacked on top of a cone. They both share a circular base. The radius of the circle is 6 millimeters. The he

kherson [118]

Answer:

312π mm3

Step-by-step explanation: yes

5 0

3 years ago

Read 2 more answers

Each package of pens contains 3 pens. How is the number of pens related to the number of packages?

yuradex [85]

Answer: The correct option is (C) Packages x 3 = Pens

Step-by-step explanation: Given that each package of pens contains 3 pens.

We are to choose the correct mathematical relation between number of pens and number of packages.

Let, n represents the number of pens and N represents the number of packages.

Then, according to the given information, we have

$n\times 3=N\\\\\Rightarrow \textup{Packages}\times 3=\textup{Pens}.$

Thus, the correct relation is

Packages x 3 = Pens.

Option (C) is CORRECT.

6 0

3 years ago

An experiment was conducted to observe the effect of an increase in temperature on the potency of an antibiotic. Three 1-ounce p

ludmilkaskok [199]

Answer:

a) $y=-0.317 x +46.02$

b) Figure attached

c) $S^2=\hat \sigma^2=MSE=\frac{190.33}{10}=19.03$

Step-by-step explanation:

We assume that th data is this one:

x: 30, 30, 30, 50, 50, 50, 70,70, 70,90,90,90

y: 38, 43, 29, 32, 26, 33, 19, 27, 23, 14, 19, 21.

a) Find the least-squares line appropriate for this data.

For this case we need to calculate the slope with the following formula:

$m=\frac{S_{xy}}{S_{xx}}$

Where:

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}$

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}$

So we can find the sums like this:

$\sum_{i=1}^n x_i = 30+30+30+50+50+50+70+70+70+90+90+90=720$

$\sum_{i=1}^n y_i =38+43+29+32+26+33+19+27+23+14+19+21=324$

$\sum_{i=1}^n x^2_i =30^2+30^2+30^2+50^2+50^2+50^2+70^2+70^2+70^2+90^2+90^2+90^2=49200$

$\sum_{i=1}^n y^2_i =38^2+43^2+29^2+32^2+26^2+33^2+19^2+27^2+23^2+14^2+19^2+21^2=9540$

$\sum_{i=1}^n x_i y_i =30*38+30*43+30*29+50*32+50*26+50*33+70*19+70*27+70*23+90*14+90*19+90*21=17540$

With these we can find the sums:

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=49200-\frac{720^2}{12}=6000$

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}=17540-\frac{720*324}{12}{12}=-1900$

And the slope would be:

$m=-\frac{1900}{6000}=-0.317$

Nowe we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{720}{12}=60$

$\bar y= \frac{\sum y_i}{n}=\frac{324}{12}=27$

And we can find the intercept using this:

$b=\bar y -m \bar x=27-(-0.317*60)=46.02$

So the line would be given by:

$y=-0.317 x +46.02$

b) Plot the points and graph the line as a check on your calculations.

For this case we can use excel and we got the figure attached as the result.

c) Calculate S^2

In oder to calculate S^2 we need to calculate the MSE, or the mean square error. And is given by this formula:

$MSE=\frac{SSE}{df_{E}}$

The degred of freedom for the error are given by:

$df_{E}=n-2=12-2=10$

We can calculate:

$S_{y}=\sum_{i=1}^n y^2_i -\frac{(\sum_{i=1}^n y_i)^2}{n}=9540-\frac{324^2}{12}=792$

And now we can calculate the sum of squares for the regression given by:

$SSR=\frac{S^2_{xy}}{S_{xx}}=\frac{(-1900)^2}{6000}=601.67$

We have that SST= SSR+SSE, and then SSE=SST-SSR= 792-601.67=190.33[/tex]

So then :

$S^2=\hat \sigma^2=MSE=\frac{190.33}{10}=19.03$

5 0

3 years ago

A $10 decrease followed by a $15 increase

Leto [7]

That’s not the full question but if it was it would be greater bc 10 - 10=0 but 10-10+15 would equal 15 instead of 10

3 0

2 years ago

If h(x) = (fºg)(x) and h(x)= 5(x+1)^3 find one possibility for f (x) and g(x).

viktelen [127]

Answer:

One possibility is that;

g(x) = (x + 1)

while h(x) = 5x^3

Step-by-step explanation:

Here, we are told to find one possibility for f(x) and g(x)

The term h(x) = (Fog)(x) means that we are inserting g(x) into f(x) to give h(x)

Now let’s have it this way;

We can see that g(x) = (x + 1) , then h(x) = 5x^3

This is one possibility of the values of g(x) and h(x)

6 0

3 years ago