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2 years ago

What is the value of this expression when a = 7 and b=-4?

Mathematics

2 answers:

dexar [7]2 years ago

7 0

$(2(7)) - ( \frac{ - 4}{ 3} ) \\ 14 + ( \frac{4}{3} ) \\ \frac{14}{1} + \frac{4}{3} \\ \frac{18}{3} = 6 \\ d.6$

s344n2d4d5 [400]2 years ago

4 0

<h2>VALUE OF |2a| - b/3</h2>

Answer:

The value of the expression |2a| - b/3 is $\blue{15.\overline{3}}$ or $\blue{15 \dfrac{1}{3}}$ .

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Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So $\triangle ABC$ and $\triangle ABD$ Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

First in triangle ABC

perpendicular=p=8cm

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We need to find base=b

According to Pythagoras thereon

${\boxed{\sf b^2=h^2-p^2}}$

Substitutethe values

$\longrightarrow$ $\sf b^2=10^2-p^2$

$\longrightarrow$ $\sf b={\sqrt {10^2-8^2}}$

$\longrightarrow$ $\sf b={\sqrt{100-64}}$

$\longrightarrow$ $\bf b={\sqrt {36}}$

$\longrightarrow$ $\sf b=6$

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$\longrightarrow$ $BD=9+6$

$\longrightarrow$ $BD=15cm$

Now in $\triangle ABD$

Perpendicular=p=8cm

Base =b=15cm

We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

${\boxed {\sf h^2=p^2+b^2}}$

Substitute the values

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$\longrightarrow$ $\sf h={\sqrt {8^2+15^2}}$

$\longrightarrow$ $\sf h={\sqrt {64+225}}$

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2 years ago

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Answer:

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Step-by-step explanation:

Here, we want to write the given statement in algebraic form

What number exceeds m by five more than n

Let the number be x

x-m = n + 5

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6 r4
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~~~~~~~~~

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2 years ago

Read 2 more answers

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Answer:

x + 6 + x + 6 + x + 6 + x + 6 + x + 6 x + 6 + x + 6 + x + 6 = 120

aka 8(6 + x) = 120

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