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VikaD [51]
3 years ago
13

How many solutions will the following system of linear equations have?

Mathematics
1 answer:
devlian [24]3 years ago
8 0
For the answer to the question above, 
2x + 4y = –7 (1)
y = -1/2x + 5 (2)
Putting (2) into (1), we have:
-2x + 4(-1/2x + 5) = -7
-2x - 2x + 5 = -7
-4x = -7 - 5 = -12
x = -12/-4 = 3
y = -1/2(3) + 5 = -3/2 + 5 = 7/2
Therefore there is only one solution
I hoipe my answer helped you. Feel free to ask more questions. Have a nice day!
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using the multiplication property of equality to multiply both sides of the equation by 10

Step-by-step explanation:

Given equation is:

\frac{x+3}{2} = \frac{3x+5}{5}

One method to solve this equation is cross-multiplication which the student has used.

One of the alternate method can be multiplying both sides by the LCM of numerators of fractions on both sides

So multiplying both sides by 10 (multiplication property of equality)

\frac{x+3}{2} * 10 = \frac{3x+5}{5} * 10\\5(x+3) = 2(3x+5)\\5x+15 = 6x+10\\5x+15-10 = 6x\\6x = 5x+5\\6x-5x = 5\\x = 5

The alternate method of LCM produces the same answer so the correct answer is:

using the multiplication property of equality to multiply both sides of the equation by 10

Keywords: Linear equations, variables

Learn more about linear equations at:

  • brainly.com/question/11229113
  • brainly.com/question/11234838

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