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3 years ago

Find the midpoint between 1,5 and 7,-3

Mathematics

1 answer:

vivado [14]3 years ago

6 0

Answer:

the midpoint is (4,0)

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Complete the table of values for the equation y = 3x + 5.

cricket20 [7]

f(x)=3x+5

f(-2)=3×(-2)+5

= -6+5

=-1

f(-1)=3×(-1)+5

=-3+5

f(0)=3×0+5

=0+5

f(1)=3×1+5

=3+5

f(2)=3×2+5

=6+5

=11

3 0

2 years ago

Determine if triangle ABC with coordinates A (0, 2), B (2, 5), and C (−1, 7) is an isosceles triangle. Use evidence to support y

kirill115 [55]

Answer:

The triangle ABC is an isosceles right triangle

Step-by-step explanation:

we have

The coordinates of triangle ABC are

A (0, 2), B (2, 5), and C (−1, 7)

we know that

An isosceles triangle has two equal sides and two equal internal angles

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

substitute in the formula

$d=\sqrt{(5-2)^{2}+(2-0)^{2}}$

$d=\sqrt{(3)^{2}+(2)^{2}}$

$dAB=\sqrt{13}\ units$

step 2

Find the distance BC

substitute in the formula

$d=\sqrt{(7-5)^{2}+(-1-2)^{2}}$

$d=\sqrt{(2)^{2}+(-3)^{2}}$

$dBC=\sqrt{13}\ units$

step 3

Find the distance AC

substitute in the formula

$d=\sqrt{(7-2)^{2}+(-1-0)^{2}}$

$d=\sqrt{(5)^{2}+(-1)^{2}}$

$dAC=\sqrt{26}\ units$

step 4

Compare the length sides

$dAB=\sqrt{13}\ units$

$dBC=\sqrt{13}\ units$

$dAC=\sqrt{26}\ units$

$dAB=dBC$

therefore

Is an isosceles triangle

Applying the Pythagoras Theorem

$(AC)^{2} =(AB)^{2}+(BC)^{2}$

substitute

$(\sqrt{26})^{2} =(\sqrt{13})^{2}+(\sqrt{13})^{2}$

$26=13+13$

$26=26$ -----> is true

therefore

Is an isosceles right triangle

8 0

3 years ago

What is equivalent to 16/81

Lady_Fox [76]

There are a lot of things that are equivalent to 16/81.

16/81 = 0.197530864

Or we can keep multiplying 2 to the numerator and denominator:

16/81 = 32/162 = 64/324 = 128/648

4 0

3 years ago

Read 2 more answers

Non examples of graphs

Kipish [7]

A Non-example is like there we not enough to grapha

5 0

2 years ago

Read 2 more answers

Select the domain and range<br><br> Will give 100 points

8090 [49]

The domain is (-3,0) U (2,4)
The range is (-2,-1) U (1,2)

7 0

2 years ago

Find the midpoint between 1,5 and 7,-3 ​

Find the midpoint between 1,5 and 7,-3